Question

12.22 g of the monoprotic acid KHP(MW = 204.2 g/mol) is dissolved into water. The sample is titrated with a 0.85 M solution of calcium hydroxide to the equivalence point. What volume of base was used?

Answer 1

Volume used 35.2 ml

=> Males of Acid [ht] = males of OH males of OH * at equivalence Point Nou males of KAP G. W Mow 204.2 gm 12.22 gm 0.0598 mal moles of Oh at equivalence point 0.0598 But Calcium hydroxide (ca conde] is di basic releases means 2 OH РФ та Se males of La Coule used 0.0598 0.0299 Now Malarity no of m moles X 1ooo Volume in (me) 0.85 M Oo0299 x 100 o Volume in me Volume in ml = 35.2 ml Ary
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