Determine the magnitude of the force between two point charges. Q1 = -750 e located at...

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Answer 1

Answer #1

$r^2 = \left((4.5+7.6)^2 + (1.6 +3.8) ^2 \right ) \times 10^{-4} m^2 = 1.75 \times 10^{-2} m^2$

$E = \frac{kq_1q_2}{r^2} = \frac{9 \times 10^{9} \times 750 \times 356 \times (1.6 \times 10^{-19})^2}{1.75 \times 10^{-2}}$

$E = 3.5 \times 10^{-21} N/C$

Answer 2

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