write solution of x''+9x = sin(2t) x(0)=0 and x'(0)=1 as the sum of two oscillations
The complementary solution is
x = Asin(3t) + B cos(3t) or C*sin(3t + φ)
The particular integral would be of the form
x = a*sin(2t)
x" = -4a*sin(2t)
x" + 9x = 5a*sin(2t)
a = 1/5
Final solution:
x = C*sin(3t + φ) + (1/5) * sin(2t)
First oscillation is C*sin(3t + φ)
second is (1/5) * sin(2t)
write solution of x''+9x = sin(2t) x(0)=0 and x'(0)=1 as the sum of two oscillations
Given sin 8-sin 9x=0 Find the solution that corresponds to the positive k=1 solution for the cosine part.
1 point) Check by differentiation that y 3 cos 2t+3 sin 2t is a solution to y" 4y 0 by finding the terms in the sum: y" 4y So y" +4y
use the product-to-sum formula to rewrite the product as a sum or difference. sin(9x) sin(4x)
2. x" + 6x' + 18x sin 2t, x(0) = -1, x'0) = 1.
If sin(x) = and cos(x) < 0 and 0 (5) and sin⑨ x < 2T. determine the exact value of cos If sin(x) = and cos(x)
Solve the given initial-value problem. dax + 4x = -7 sin(2t) + 6 cos(2t), x(0) = -1, x'(0) = 1 xce) = -cos(2+) – sin(2t) + {cos(21) + (sin(21) Need Help? Read It Watch It Talk to a Tutor
Q a cos 7x- cos 9x The graph with the equation y= is shown sin 7x + sin 9x in a [0,2x,x] by [-2.2.1] viewing rectangle. a. Describe the graph using another equation. b. Verify that the two equations are equivalent 22 a. Write another equation of the given graph y = tan x (Type an equation using x as the variable) b. To verify that the two equations are equal, start with the numerator of the right side and...
4 Linearize the following ODE around Xo 2T,u,-1 0 0 x 2 sin(x) + xu + u2
is shown cos 7x- cos 9x The graph with the equation y sin 7x + sin 9x in a [0,2xx] by [-2.2.1) viewing rectangle a. Describe the graph using another equation b. Verify that the two equations are equivalent D a. Write another equation of the given graph (Type an equation using x as the variable) b. To verify that the two equations are equal, start with the numerator of the right side and apply the appropriate sum-to product formula...
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