The answer is
(a) Vc = 10+1.708e^(-2.618x10^4)t -
11.708e^(-0.3820x10^4)t
(b) Vc = 10-10e^-10^4t - (10^5)te^10^-4t
(c)...
3 Cal culate vd0) for each ca se of a, R-300 Ω, b. R-200 Ω, and c. R-100Ω. (1.5) ) + RMA + LCVc(t) att=0 and initial conditions are/(0)-0 and 1a0) 0 L=10mH NOTE: The governing equation is d LC i(t) V, 10V