A hollow sphere starts from rest and rolls down a hill without sliding. At the bottom of the hill, it has a linear velocity of 5 m/s. What was the height of the hill the sphere rolled down (in meters)?
from the law of conservation on energy
mgh = 0.5 mv^2 + 0.5 I w^2
I is moment of inertia = 2mr^2/3
W = V/r
so
gh = 0.5 mv^2 + 1/3 * m r^2 * V^2/r^2
9.8 * h = 0.5* 5^2 + 1/3 * 5^2
h = 2.125 m
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