1. (20 points) A hollow sphere of radius r and mass m starts from rest and rolls down the mountainside and then up...

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Answer 1

Answer #1

using conservation of energy

mg Ho = 0.5 m v^2 + 0.5 Iw^2

mg Ho = 0.5.m v^2 + 0.5* ( 2 / 3) m r^2 ( v^2/r^2)

g Ho = 0.5 v^2 + 0.333 v^2

v^2 = 1.2 g Ho

now since in smooth surface no friction present means, the ball won't rotate on that surface

so we can simply use 3rd equation of motion

h= v^2/ 2g

h = 1.2 g Ho / ( 2g)

h = 0.6 Ho

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Comment before rate in case any doubt, will reply for sure.. goodluck

Answer 2

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