Question

Please paste your code and a screenshot of your output!

1. An integer n is divisible by 9 if the sum of its digits is divisible by 9. Develop a program to determine whether or not the following numbers are divisible by 9: n= 154368 n 621594 n-123456 2. A number is said to be perfect if the sum of its divisors (except for itself) is equal to itself. For example, 6 is a perfect number because the sum of its divisors (1 + 2 + 3) is 6. The number 8 is said to be deficient because the sum of its divisors (1 + 2 + 4) is only 7. The number 12 is said to be abundant because the sum of its divisors (1 + 2+ 3 + 4 + 6) is 16. Write a program that lists the factors of the numbers between 1 and 100 and classifies each number as perfect, deficient, or abundant. What to submit: Submit your .cpp file and screenshot of your sample Input and output.

Answer 1

Solution #include <iostream> using namespace std; int main() //declare the number num as integer variable int num //initializes the digit sum ds is 0 int ds- 0; //declare the variable f r digit d int d: //get the number cout<<"Enter number:" cin>>num; //initializes the given num to res int res = num ; /lusing loop add the digit of one by one number while (num) = num % 10; num /= 10; //check the given digit sum is divisible by 9 or not if (da % 9) cout <<res<<" is not divisible by 9"; else cout <<res<<" is divisible by 9"; return 0
Copyable Code:

1.

#include <iostream>

using namespace std;

int main()

{

    //declare the number num as integer variable

    int num;

    //initializes the digit sum ds is 0

    int ds= 0;

    //declare the variable for digit d

    int d;

    //get the number

    cout<<"Enter number: ";

    cin>>num;

    //initializes the given num to res

    int res = num;

    //using loop add the digit of one by one number

    while (num)

    {

        d = num % 10;

        ds += d;

        num /= 10;

  }

    //check the given digit sum is divisible by 9 or not

    if (ds % 9)

        cout<<res<<" is not divisible by 9";

    else

        cout<<res<<" is divisible by 9";

  

    return 0;

}

2.

#include <iostream>

using namespace std;

int main()

{

    //declare the variable

    int num,i,sum=0;

    //get the number

    cout<<"Enter a number: ";

    cin>>num;

    //print the factors ofgiven input number

    cout<<"Factors of "<<num<<" are: ";

    //using loop, find the factor and sum

    for(i=1;i<num;++i)

    {

        if(num%i==0)

        {

           cout<<" "<<i<<" ";

           sum=sum+i;

        }

    }

    cout<<"\n";

    //check if the sum is equal to given number, then it is perfect number

    if(sum==num)

    {

     cout<<"The given number "<<num<<" is a perfect number";

    }

    //otherwise

    else

    {

        //check if the sum is less than to given number, then it is deficient number

        if(sum<num)

        {

          cout<<"The given number "<<num<<" is a deficient number";

        }

        //otherwise, it is abundant number

        else

        {

          cout<<"The given number "<<num<<" is an abundant number";

        }

    }

return 0;

}