Question

esges Courses Help Logout Course Contents > Unit 6: Torque Hw 6.3: Equilibrium revisited oes AUTO SERVICE0.80 m FREE ESTIMATES 1.00 m You are asked to hang a uniform beam and sign using a cable that has a brealking strength of 417 N. The store owner desires that it hang out over the sidewalk as shown. The sign has a weight of 200.0 N and the beam's weight is so.O N. The beam's length is 1.50 m and the sign's dimensions re 1.00 m horizontally x 0.80 m vertically. What is the minimum angle 8 that you can have between the beam and cabe? Submit Ansawer Tries 1/99 Previous Tries Send Feedback Post Discussion 11/13/2018 O Type here to search DOLL Priser insert FB F6 F7 FS F3 Esc 84

Answer 1

Solution :-

equating torques:

(200×1)+ (50×0.75) = 427×sin(x)×(1.5)

So, x = 22.3 degrees