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Chemical Equilibrium and Chemical Kinetics < 17 of 17 > - Part 8 For a different reaction K kr. after adding catalyst? -473-1
Review Constants Periodic Table Part B The equilibrium constant of a reaction of a particular temperature is determined by th
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Ane) Given Data is a) Kc 4.73x105. - Kf = 8.38x1035 kg 2 1.97 xjö? 57 Forward rate constant = 3.52x10 st. We already know theWe have to find ka value After adding a Со Catalyst. : : . Kor= 3.52x16 51 4.73 xics Kor= 3.52 Kor: 0.74418 st b) Given. DataSince. [12] combination = 0.0700 = 0.0400 = 2.85-X 0.07 - 2.85-7 x 2.85-0.07 The following concentrations are get 3.75-X = 3.. Let or find out Equilibrium constant 0 kc from Ice table (5.56) Kc = (0.97)(0.07) 30.9136 kez 0.0679 1 Kc = 455.2812 .. Equ

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