Question

What is AHºrxn for the following reaction based on the standard reaction enthalpies given below? AHºrn = ? 2 NO(g) + O2(g) +2 NO2(g) Given: N2(g) + O2(g) → 2 NO(g) 1/2 N2(g) + O2(g) NO2(g) AHºrn = +183 kJ AHºrn = +33 kJ A. -150 kj B.-333 kJ C. +115 kJ OD. +238 kJ E. -117 kJ

Answer 1

N2(g) + O2(g) = 2 NO(g). ∆H° = 183 KJ

Reverse the equation

2 NO(g) = N2(g) + O2(g). ∆H° = -183 KJ i

1/2 N2(g) + O2(g) = NO2(g). ∆H° = 33 kJ

Multiply by 2

N2(g) + 2O2(g) = 2 NO2(g). ∆H° = 2*33 = 66 Kj. ii

Add equation i and ii

2 NO(g) + O2(g) = 2 NO2(g)

∆H° = -183 + 66 = -117 KJ

Option E

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