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Confidence interval for the population mean: Use of the t distribu... A researcher collected sample data for 10 women ages 18

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ANSWER:

Given that,

X192.4

S = 5.2

n =10

degrees of freedom = n -1 =10 -1 = 9

The 99% confidence interval for \mu is,

土th-1.a/2

192.4 t t0.005*5.2/V10

192.4 3.690*5.2/V10

192.4 6.07

186.3, 198.5)

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