(a)
Probability that a score is between z and - z is 0.84.
So,
Area from mid value to Z on either side = 0.42
Table of Area Under Standard Normal Curve gives Z = 1.405.
So,
Answer is:
1.405
(b)
n = 50
p =0.8
q = 0.2
Mean = np = 50 X 0.8 = 40
Variance = npq = 50 X 0.8 X 0.2 = 8
standard deviation = = 2.8284
-1 points RolFM8 8.7.074 Assume normal distribution in the following exercise. Find the value of z....
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