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- At Western University the historical mean of scholarship examination scores for freshman applications is 900. Each year the
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Answer #1

(a)
H0: Null Hypothesis: \mu = 900 (The mean examination score for new freshman applications has not changed)

HA: Alternative Hypothesis: \mu \neq 900 (The mean examination score for new freshman applications has changed) (Claim)

(b)

n = 75

\bar{}\bar{x} = 875

\sigma = 100

SE = \sigma /\sqrt{n}

= 100/\sqrt{75}

= 11.5470

Test Statistic is given by:

Z = (875 - 900)/11.5470

= - 2.1651

(c)

Table of Area Under Standard Normal Curve gives area = 0.4850

So,

p - value = (0.5 - 0.4850) X 2 = 0.03

Since p - value = 0.03 is less than \alpha = 0.05, the difference is significant. Reject null hypothesis.

Conclusion:
The data support the claim that the mean examination score for new freshman applications has changed.

(d)

\alpha = 0.05

From Table, critical values of Z = \pm 1.96

Since calculated value of Z = - 2.1651 is less than critical value of Z = - 1.96, the difference is significant. Reject null hypothesis.

Conclusion:
The data support the claim that the mean examination score for new freshman applications has changed.

(e)

The mean examination score for new freshman applications has changed.

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