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It is reported that the ACT scores of freshman students at NMSU is approximately Normally distributed, with mean of 20.5 and
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Answer #1

Answer:

Given,

X ~ N(20.5 , 5.1^2)

1)

P(X > x) = 0.03

P(z > (x - 20.5)/5.1) = 0.03

P(z > 1.88) = 0.03

since from standard normal table

z = 1.88

(x - 20.5)/5.1 = 1.88

x = 30.088

2)

Xbar ~ N(20.5 , 5.1^2/20) ~ N(20.5 , 1.3005)

P(Xbar > 22) = P(z > (22 - 20.5)/1.3005)

= P(z > 1.15)

= 0.1250719 [since from z table]

= 0.1251

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