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I cannot figure this problem out, if you could show all the steps that would be great.
Characterize the below integrals (definite or indefinite) and solve the integrals by using the substitution rule: a. S(-11(5x + 7)5)dx b. S(4V7x - 1)dx C. J-8 siz3x cosx) dx d. S -6 dx 2x+3 e. S(-5sin(9x - 4))dx
Characterize the below integrals (definite or indefinite) and solve the integrals by using the substitution rule: 9+x2 dx b. J v1+ cosx + sinxdx
9-15. Locate the centroid of the shaded area. Solve the problem by evaluating the integrals using Simpson's rule. =0
set up iterated integrals for both orders of integration. then evaluate the double integral using the easier order and explain why it's easier. D y dA, D is bounded by y = x - 2, x=y2 (the D next to the double integral should be under the integral. I don't know how to put it in the right spot.
Set up iterated integrals for both orders of integration. Then evaluate the double integral using the easier order. ∫∫DydA, D is bounded by y = x -30; x = y2
Characterize the below integrals (definite or indefinite) and solve the integrals: a. (-10x5 + 3x2 - 5x)dx b. S(-8Vx)dx C. SCEx _17) ax d. S(12e* - 9 sin x + 5x-2)dx 5 (6********=)dx
Characterize the below integrals (definite or indefinite) and solve the integrals: a. (5x2 + 7x4 + 50) dx b. f (6e* - 7cos x + 14)dx c. Si (-5sinx + 3) dx
using double angle identity solve 10sin2x+cosx =0