Answer:
Compound formula is C5H10O. Let us calculate the double bond equivalent or degree of unsaturation.
Degree of unsaturation = No. of C - (No. of H/2) + (No. of N/2) + 1 = 5 - 10/2 + 1 = 1
Therefore, there is a possiblity of one ring or one double bond to be present.
The C13 peaks from higher ppm range to lower ppm range corresponds to doublet, triplet, triplet, quartet, triplet as per question.
Protons are spin 1/2 nuclei. Multiplicity of C13 peaks due to coupling is (n+1), where n is the no. of protons.
Hence from higher ppm range to lower ppm range the residues are -CH (above 130 ppm), -CH2, -CH2, -CH3, -CH2 (below 40 ppm).
Above 110 ppm there are two peaks doublet and triplet. This is alkene region. So one residue will look like -CH=CH2.
The peaks near 60 ppm and 80 ppm are for those carbons attached to Oxygen atom.
Hence there will be a residue like CH3-O-CH2-
The triplet just above 30 ppm is for aliphatic -CH2- which is flanged between CH3-O-CH2- and -CH=CH2 residues.
Hence the most probable structure is CH3-O-CH2-CH2-CH=CH2
.......................
** please help with this ** 8. CH1,0 IR: nothing interesting The spectrum displayed is a...
Compound is a liquid, boiling point 136 C. The Mass, IR, and H NMR spectra, along with C NMR data, are given below. Elemental Analysis: C, 90.51; H, 9.49. Mass Spectrum 106 30 50 70 500 110 120 130 140 150 100 170 ao 10 2001 mie Infrared Spectrum Wave Number, om 4000 3000 2500 2000 1500 1300 1200 100 1000 900 10 13 11 Wavelength, microns H NMR 2 pom, & Structure: C Spectral Data: singlet, 140.2 ppm doublet,...
Question 5: (11 marks) Compound B, which contains only carbon, hydrogen and oxygen atoms, shows the mass, IR, H NMR and C NMR spectra given below a) With brief explanation, deduce the structure of Compound B b) Explain the mass spectroscopic signals at m/z 122, 105 and 77. Mass Spectrum 122 M° 150 70 90 100 110 120 130 140 150 150 170 180 100 200 mve Infrared Spectrum Wave Number,cm- 4000 3000 250 2000150 13 1 11001000900 80 Wavelengihn,...
help! what is the structure deduced from the IR and NMR?
please help!
3. MF: CeH11BrO2 IR: 30- 25- 20- 15- 10- 3000 3500 2500 2000 1500 1000 Wavenumber (cm-1) H-NMR: 11.5 ppm (singlet; integral 1), 2.5 ppm (triplet; integral = 2), 1.5 ppm (singlet; integral 3), 1.3 ppm (sextet; integral 2), and 1.0 ppm (triplet; integral = 3) 4. MF: C10H15N IR: 4800 as00 sevENu 'H-NMR: 7.0-7.5 ppm (multiplet; integral 1.25), 3.6 ppm (quartet; integral 1.0), and 1.4 ppm...
Need help proposing a structure given the following
data.
23. The mass spectrum shows M = 72, IR shows a strong peak near 1720 cm! C-NMR shows four lines. The proton NMR is tabulated below. 2.4 ppm (2H quartet) 2.1 ppm (3H singlet) 1.1 ppm (3H triplet)
FOR EACH DETERMINE (if applicable):
• MS DATA
• IR DATA
• HNMR DATA
• CNMR DATA
• MOLECULAR FORMULA
• MOLAR MASS
• STRUCTURE AND EVIDENCE
Compound 56 is a high-boiling liquid (boiling point 229 C) that does not react with I, in aqueous base to give a yellow precipiale of CHI, (a negative iodoform test). The Mass, IR, and 'H NMR spectra, along with 1C NMR data, are given below. Analysis: Elemental C, 81.04; H, 8.16; O, 10.80....
Use the mass spectrum and either the NMR spectrum or the IR
spectrum to deduce the structure of the following compound
(c) C8HO3H NMR, 300 MHz, 6.1 ppm (singlet, 2H), 6.9 ppm (doublet, 1H), and 7.3 ppm (singlet, 1H), 7.4 ppm (doublet, 1H), 9.8 ppm (singlet, 1H); significant IR absorbances at 1687, 1602, 1449, 1264, 1038, 929, and 815 cm1. 100 149 (150) 80 60 40 121 63 20 65 91 0 15 20 25 30 35 40 45 50...
2. Use the 'H NMR and IR data to determine the structure of the following compounds and name them. Compound A Molecular formula: CroH IR absorptions at N/A H NMR data: 1.3 (singlet, 9H), 7.0 to 7.5 (multiplet, 5H) ppm Compound B Molecular formula: CHO IR absorptions at 1H NMR data: 1735-1745, 1050 cm 0.93 (doublet, 6H), 1.52 (multiplet, 2H), 1.69 (multiplet, 1H), 2.04 (singlet, 3H), and 4.10 (triplet,2H) ppm Compound C Molecular ion: IR absorptions at 1710 cm 1H...
for the following 2 compounds, please calculate, and
show the calculations for, the degree of unsaturation, assign the
IR spectrum peaks, assign the 13C NMR peaks, assign the 1H NMR
peaks, and draw the structure for the unknown compound.
CHIM 245 Spectroscopy Problem Set #2 In this problem set there are two unknown compounds. You are provided with the formula, IR spectrum, "C NMR spectrum, and 'H NMR spectrum for each compound. Each unknown is worth 10 points, with an...
Using the NMR, IR, and MS figure out what the compoud is.
**
identify the molecular structure througu NMR, IR and MS
CHEM 100L Lab 3 NMR Problems Unknown 1 CH 0 M-a 102 Relative Intensity 20 30 40 50 70 80 60 m/z water, not part of sample 1-2975-2877 9H, singlet 2H, 3H, quartet triplet ppm Unknown 2 C,H,O tensity 119 Relative 3200-2600 1680V 3H, singlet 2x 2H, doublet 1H, singlet ppm Unknown 3 C,HO, Relative Intensity 3090 3035...
20. Propose a structure for compound GHOST with a formula C.HO, with the tom spectrum and IR spectrum. *O2 with the following 'H NMR TRANSACTIEF 21 4000 HAVENUMERI Chem Shift Rel. Area Splitting 4.1 2.0 1.7 1.5 0.9 triplet singlet nonet quartet doublet EN ppm