Question

Compound is a liquid, boiling point 136 C. The Mass, IR, and H NMR spectra, along with C NMR data, are given below. Elemental Analysis: C, 90.51; H, 9.49. Mass Spectrum 106 30 50 70 500 110 120 130 140 150 100 170 ao 10 2001 mie Infrared Spectrum Wave Number, om 4000 3000 2500 2000 1500 1300 1200 100 1000 900 10 13 11 Wavelength, microns H NMR 2 pom, & Structure: C Spectral Data: singlet, 140.2 ppm doublet, 128.4 pPpm doublet, 127.9 Ppm doublet, 125.7 ppm triplet, 31.1 ppm quartet, 16.1 ppm c2000 Brooks/Cole Publishing Company Absorbance Inmensity

Answer 1

So it is In The Mast spectrum , highert m/2 Value is lob Clean that Molecular Mall of Compound its loby. Three Signals are observed in which u Characterstic of 'H NMR Aromatic Peak is and one Compound- around 7 Also le NMR signals which are at ( 140-2 ppm, 128:4ppm, 127.9 Prm, R5 7 fm) uridicate Aromaticity in Compound- Interfreation → Moleculor Weight - 1063 Since Combound only Contains Carbon One possible formula Can be Callio and hydrogen Therefore Double bond Equivalent - (Hof Lorben +1) - lood 11 9-5=4 So Compound con be

E q will Satisfy all the Spectras © Singlet around 8=7 ® Quarket around 8-2.5 © Triblet around 8-1 It will also satisfy a stable Cation Mall Spectrum because it will form which gives Peck at 91 2 So Our Compound is Ethyl bemene [