Question

A force F = At acts on an object from time t = 0 to time...

A force F = At acts on an object from time t = 0 to time t = T, where A is a constant. The impulse given to the object over this time period is?

A) A

B) AT

C) (AT)/2

D) (AT^2)/2

E) AT^2

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Use the definition of impulse and integration to find the required solution as shown belowimpulse =

***********************************************************************************************
Check the answer and let me know immediately if you find something wrong or missing... I will rectify the mistakes asap if any

Add a comment
Know the answer?
Add Answer to:
A force F = At acts on an object from time t = 0 to time...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Exercises 1. Suppose a force acts on a 4.00 kg object in the x-direction. The force varies with t...

    Exercises 1. Suppose a force acts on a 4.00 kg object in the x-direction. The force varies with time and is given by F(t)12.0t3 - 8.00 N. At t -0, the object has a velocity of 3.00 m/s in the positive x-direction. Use the impulse-momentum theorem to find the object's velocity after 2.00 s. 2. In a lab experiment, a spring gun projects a metal sphere. The sphere leaves the spring gun with a velocity of 3.00 m/s in the...

  • The impulse of an object is 1 a. the product of (the peak force applied to...

    The impulse of an object is 1 a. the product of (the peak force applied to an object) x (time interval during which the force acts). 2 b. the product of (the average force applied to an object) x (time interval during which the force acts). 3 c. the average force applied to an object for a period of 1 sec. 4 d. the peak force applied to an object for a period of 1 sec. 5 e. the total...

  • An object of mass m is initially at rest. After a force of magnitude F acts...

    An object of mass m is initially at rest. After a force of magnitude F acts on it for a time T, the object has a speed v. Suppose the mass of the object is doubled, and the magnitude of the force acting on it is quadrupled. In terms of T, how long does it take for the object to accelerate from rest to a speed v now? T′/T T′/T =

  • #8 2. Consider the force F shown in the drawing. This force acts on an object...

    #8 2. Consider the force F shown in the drawing. This force acts on an object that can move along the F positive or negative x axis, or along the positive or negative y axis. The work done by this force is positive when the displacement of the object is along the axis: (a)-x, -y (b)-x, +y (c) +x, +y circular pat What enabl is above po by the tens energy gravitation axis or along the Section 6 and the...

  • At the time t = 0 s, an object of mass m = 10.5kg goes through...

    At the time t = 0 s, an object of mass m = 10.5kg goes through the origin of a reference frame with at velocity x_0 = 12.0 m/s directed along the x axis. A constant force F = 15 N distorted along the y axis is applied to the object. a) Draw a free body diagram of the object. b) Calculate the magnitude of the object's acceleration. c) Calculate the x and y coordinate of the object at the...

  • A single force acts on a 0.92 kg particle-like object in such a way that the...

    A single force acts on a 0.92 kg particle-like object in such a way that the position of the object as a function of time is given by x = 3.2t - 2.6t2 + 3.1t3, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 3.2 s.

  • Question 3 A single force acts on a 1.2 kg particle-like object in such a way...

    Question 3 A single force acts on a 1.2 kg particle-like object in such a way that the position of the object as a function of time is given by x = 1.0t - 3.22 + 3.5+, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 5.9 s. Number Units the tolerance is +/-2%

  • A force Fi f 6.30 unts acts on an object at the origin in 0- 51.0°...

    A force Fi f 6.30 unts acts on an object at the origin in 0- 51.0° above the positive x-axis. (See the figure below.) second force F2 of magnitude 5.00 units acts on the object in the direction of the postive y-axis. Find graphicaly the magnitude and direction of the resultant force FiF magnitude direction

  • A force F of magnitude 6.20 units acts on an object at the origin in a...

    A force F of magnitude 6.20 units acts on an object at the origin in a direction 0 29.00 above the positive x-axis. (See the figure below.) A second force F, of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find graphically the magnitude and direction of the resultant force F1F2. units magnitude O counterclockwise from the +x-axis direction

  • Consider a situation where a constant force of 25N acts on an object having a mass...

    Consider a situation where a constant force of 25N acts on an object having a mass of 2kg for 3 seconds. What is the work done by the force? A) 150J B) 50J C) 75J D) undetermined - not enough information E) none of the above

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT