A single force acts on a 0.92 kg particle-like object in such a way that the position of the object as a function of time is given by x = 3.2t - 2.6t2 + 3.1t3, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 3.2 s.
A single force acts on a 0.92 kg particle-like object in such a way that the...
A single force acts on a 0.54 kg particle-like object in such a way that the position of the object as a function of time is given by x = 5.0t -0.71t2 + 3.0, with x in meters and tin seconds. Find the work done on the object by the force from t=0 tot = 9.1 s. Number 198 Units
Question 3 A single force acts on a 1.2 kg particle-like object in such a way that the position of the object as a function of time is given by x = 1.0t - 3.22 + 3.5+, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 5.9 s. Number Units the tolerance is +/-2%
Q 7.127: A single force acts on a 4.3 kg4.3 kg particle-like object in such a way that the position of the object as a function of time is given by x = 4.2t + 3.1t2 + 2.2t3x = 4.2t + 3.1t2 + 2.2t3 , with xx in meters and tt in seconds. Find the work done on the object by the force from t = 1.4 st = 1.4 s to t = 3.5 st = 3.5 s . The...
PRINTER VERSION BACK NEXT Chapter 07, Problem 041 SN incorrect. with x in meters A single force acts on a particle-like object of mass m kg in such a way that the position of the object as a function of time is given by x 3.4 and t in seconds. Find the work done on the object by the force between 0 and time t. Express your answer in terms of the variables given. m(61-8)(31-(41) +) Edit Click if you...
A single, nonconstant force acts in the +?+x direction on an 5.06 kg5.06 kg object that is constrained to move along the ?x‑axis. As a result, the object's position as a function of time is ?(?)=?+??2+??4?=7.38 m?=4.57 m/s2?=0.478 m/s4x(t)=A+Bt2+Ct4A=7.38 mB=4.57 m/s2C=0.478 m/s4 How much work is done by this force from ?=0 st=0 s to ?=2.34 s?
A single conservative force acts on a 4.50-kg particle within a system due to its interaction with the rest of the system. The equation Fx = 2x + 4 describes the force, where Fx is in newtons and x is in meters. As the particle moves along the x axis from x = 1.10 m to x = 6.55 m, calculate the following. (a) the work done by this force on the particle J (b) the change in the potential...
04 Torce - (2.001 + 9.00J + J.JUK) N acts on a 2.90 kg object that moves in time interval 2.10 s from an initial posi- tion 7= (2.70i - 2.90j + 5.50k) m to a final position 72 = (-4.10i + 3.30j + 5.40k) m. Find (a) the work done on the object by the force in that time interval, (b) the average power due to the e Pare = 2 force during that time interval, and (c) the...
A particle with mass 4.0 kg is initially at rest at the origin (x=0). It then moves along the x-axis acted on by a force F(x)=18.0-2.0x2, where F is in Newtons if x is expressed in meters. Find the kinetic energy of the particle when it reaches x=3 m. A Honda Civic (mass=1090 kg) is initially traveling due East at 18.3 m/s when it suddenly collides head on with a Toyota Camry (mass=1612 kg) initially traveling due West at 31.8...
force Fx acts on a particle that has a mass of 2 kg. The force is related to the position x of the particle by the formula F 3, where C-0.5 if x is in meters and Fy is in Newton (a)What are the SI units of C? (Use the following as necessary: N and m.) (b) Find the work Wdone by this force as the partidle moves from x - 2.8 m to x - 1.6 m (C) At...
An object of mass m = 4.2 kg moves under the influence of one force. That force causes the object to move along a path given by x = 6.8 + 5.2 t + 2.8 t2, where x is in meters and t is in seconds. Calculate the work done by the force on the object from t = 2.5 s to t = 6.5 s. ____J