Question

A single, nonconstant force acts in the +?+x direction on an 5.06 kg5.06 kg object that...

A single, nonconstant force acts in the +?+x direction on an 5.06 kg5.06 kg object that is constrained to move along the ?x‑axis. As a result, the object's position as a function of time is

?(?)=?+??2+??4?=7.38 m?=4.57 m/s2?=0.478 m/s4x(t)=A+Bt2+Ct4A=7.38 mB=4.57 m/s2C=0.478 m/s4

How much work is done by this force from ?=0 st=0 s to ?=2.34 s?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

from ginen data m=s.06kg lact) = At Be ²+ Cth. XCE)= 7.38 + (4.57) E2+ (0.478) ty. dt. dra vxdt. a wa Sfida vade Ed az uxdt -

Add a comment
Know the answer?
Add Answer to:
A single, nonconstant force acts in the +?+x direction on an 5.06 kg5.06 kg object that...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A 2.55-kg object constrained to move along the x-axis is subjected to a time-varying force as...

    A 2.55-kg object constrained to move along the x-axis is subjected to a time-varying force as shown on the graph below. Find the change in the object\'s velocity over the specified time intervals. A 2.55-kg object constrained to move along the x-axis is subjected to a time-varying force as shown on the graph Find the change in the a) Between 0 s and t4.23 s s velocity over the specified time intervals. Force vs. Time Number 15 A- 199 12...

  • A 6.87-kg object constrained to move along the x-axis is subjected to a time-varying force as...

    A 6.87-kg object constrained to move along the x-axis is subjected to a time-varying force as shown on the graph below. Find the change in the object's velocity over the specified time intérvals a) Between t0s and t 5.77 s Force vs. Time Number 15 Ar=L 12 m/s Fx (N) b) Between = 4.71 s and = 10 s 0 Number .3 m/s 6. -9 -12 0 2. 4 6 10 12 14 16 18 20 c) Between 10 s...

  • Exercises 1. Suppose a force acts on a 4.00 kg object in the x-direction. The force varies with t...

    Exercises 1. Suppose a force acts on a 4.00 kg object in the x-direction. The force varies with time and is given by F(t)12.0t3 - 8.00 N. At t -0, the object has a velocity of 3.00 m/s in the positive x-direction. Use the impulse-momentum theorem to find the object's velocity after 2.00 s. 2. In a lab experiment, a spring gun projects a metal sphere. The sphere leaves the spring gun with a velocity of 3.00 m/s in the...

  • Q 7.127: A single force acts on a 4.3 kg4.3 kg particle-like object in such a...

    Q 7.127: A single force acts on a 4.3 kg4.3 kg particle-like object in such a way that the position of the object as a function of time is given by x = 4.2t + 3.1t2 + 2.2t3x = 4.2t + 3.1t2 + 2.2t3 , with xx in meters and tt in seconds. Find the work done on the object by the force from t = 1.4 st = 1.4 s to  t = 3.5 st = 3.5 s . The...

  • The force shown in the figure(Figure 1) acts on a 1.3-kg object whose initial speed is...

    The force shown in the figure(Figure 1) acts on a 1.3-kg object whose initial speed is 0.35 m/s and initial position is x=0.27m. a. Find the speed of the object when it is at the location x=0.99 m. b. At what location would the object's speed be 0.25 m/s? 0.8 0.6 0.4 0.2 0.75 1.00 0.50 Position, x (m) 0.25

  • A single force acts on a 0.92 kg particle-like object in such a way that the...

    A single force acts on a 0.92 kg particle-like object in such a way that the position of the object as a function of time is given by x = 3.2t - 2.6t2 + 3.1t3, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 3.2 s.

  • A single force acts on a 0.54 kg particle-like object in such a way that the...

    A single force acts on a 0.54 kg particle-like object in such a way that the position of the object as a function of time is given by x = 5.0t -0.71t2 + 3.0, with x in meters and tin seconds. Find the work done on the object by the force from t=0 tot = 9.1 s. Number 198 Units

  • #8 2. Consider the force F shown in the drawing. This force acts on an object...

    #8 2. Consider the force F shown in the drawing. This force acts on an object that can move along the F positive or negative x axis, or along the positive or negative y axis. The work done by this force is positive when the displacement of the object is along the axis: (a)-x, -y (b)-x, +y (c) +x, +y circular pat What enabl is above po by the tens energy gravitation axis or along the Section 6 and the...

  • A constant 12.0-N net force acts for 3.0 s on a 3.0-kg object. What is the...

    A constant 12.0-N net force acts for 3.0 s on a 3.0-kg object. What is the object's change of velocity? 12 m/s 4 m/s 3 m/s 5 m/s

  • An object is at x at t and moves along the x axis according to the...

    An object is at x at t and moves along the x axis according to the velocity-time graph shown below v (m/s) 20 10 -10 (a) What is the object's acceleration between 0 and 4.0 s? m/s2 (b) What is the object's acceleration between 4.0 s and 9.0 s? m/s2 (C) What is the object's acceleration between 13.0 s and 18.0 s? m/s2 (d) At what time(s) is the object moving with the lowest speed? (If there is more than...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT