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04 Torce - (2.001 + 9.00J + J.JUK) N acts on a 2.90 kg object that...
physics problem A force F = (9.60 N)i + (6.30 N)j + (7.00 N )* acts on a 9.40 kg mobile object that moves from an initial position of 0,- (2.40 m ) + (1.50m)) + (9.10 m ) to a final position of , - (2.00m) + (9.20m)) + (5.00m) in 5903. Find (a) the work done on the object by the force in the 5.90 s interval, (b) the average power due to the force during that interval,...
A force F = (3xi - 2xyj) N acts on an object as the object moves in the .x direction origin to .v 5.00 m (no motion in v-axis). The object has a mass m = 5.00 kg. Find the work done on the object by the force F. lf the object starts from rest, what is the final speed of the object at x = 5.00 m.?
#8 2. Consider the force F shown in the drawing. This force acts on an object that can move along the F positive or negative x axis, or along the positive or negative y axis. The work done by this force is positive when the displacement of the object is along the axis: (a)-x, -y (b)-x, +y (c) +x, +y circular pat What enabl is above po by the tens energy gravitation axis or along the Section 6 and the...
A single force acts on a 0.92 kg particle-like object in such a way that the position of the object as a function of time is given by x = 3.2t - 2.6t2 + 3.1t3, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 3.2 s.
A single force acts on a 0.54 kg particle-like object in such a way that the position of the object as a function of time is given by x = 5.0t -0.71t2 + 3.0, with x in meters and tin seconds. Find the work done on the object by the force from t=0 tot = 9.1 s. Number 198 Units
A force 7 = (7.40 N ))+ (9.70 N)} + (8.60 N JK acts on a 9.30 kg mobile object that moves from an initial position of 0; = (7.10 m )i + (4.10 m )} + (4.10 m )k to a final position of ä, - (5.80 m )i + (1.80 m )) + (7.20 m )k in 3.60 s. Find (a) the work done on the object by the force in the 3.60 s nda, interval, (b) the...
A force F = (3.10N) î +(7.20N)ị + (7.30 N) k acts on a 6.30 kg mobile object that moves from an initial position à ; = (6.60m) î + (5.40 m)ſ +(3.80 m) Ê to a final position of ds = (6.20m) î +(7.70 m) Î + (3.30 m) î in 8.50 s. Find (a) the work done on the object by the force in the 8.50 s interval, (b) the average power due to the force during that...
Question 3 A single force acts on a 1.2 kg particle-like object in such a way that the position of the object as a function of time is given by x = 1.0t - 3.22 + 3.5+, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 5.9 s. Number Units the tolerance is +/-2%
3. A force (32i +173)N acts on a particle. The particle is displaced from 7-(42i+3.7j)m to 11.7i -2.1j)m. Please find the following: A. The displacement, AF, of the particle. B. The work, W, done by the force, F, on the particle.
Question #4 20 points total):The following net force acts on a 4.00-kg object F(2x2 N)t+ (12 N) The object starts from rest and is moved from coordinates (O.00 m, 1.00 m) to (2.00 m, 3.00 m). Part A (10 poimts): Find the total work done on the object Part B (10 points):Find the final speed of the object