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04 Torce - (2.001 + 9.00J + J.JUK) N acts on a 2.90 kg object that moves in time interval 2.10 s from an initial posi- tion 7
70 A force F = (4.0 N)i + cj acts on a particle as the particle goes through displacement d = (3.0 m)i – (2.0 m)j. (Other for
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Answer #1

(70) F = 4o tc (a) w ork done =0 V Fid =0 (4+3) - 20 =0 (b) work done = 17 F.d =17 - 20=17 - 5 - 20 rc= - 2.5 El Fd -18 c = 1

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