Question

A force F = (3.10N) î +(7.20N)ị + (7.30 N) k acts on a 6.30 kg mobile object that moves from an initial position à ; = (6.60m

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Answer

= 8.55. Given P. (3.10N) +7.20N) 5 + G.30N) Ê mass ins 6.30kg muitial position dia (6.60m) 2 (6.40mg) + 6.8m) final poshon d

Add a comment
Know the answer?
Add Answer to:
A force F = (3.10N) î +(7.20N)ị + (7.30 N) k acts on a 6.30 kg...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • physics problem A force F = (9.60 N)i + (6.30 N)j + (7.00 N )* acts...

    physics problem A force F = (9.60 N)i + (6.30 N)j + (7.00 N )* acts on a 9.40 kg mobile object that moves from an initial position of 0,- (2.40 m ) + (1.50m)) + (9.10 m ) to a final position of , - (2.00m) + (9.20m)) + (5.00m) in 5903. Find (a) the work done on the object by the force in the 5.90 s interval, (b) the average power due to the force during that interval,...

  • A force 7 = (7.40 N ))+ (9.70 N)} + (8.60 N JK acts on a...

    A force 7 = (7.40 N ))+ (9.70 N)} + (8.60 N JK acts on a 9.30 kg mobile object that moves from an initial position of 0; = (7.10 m )i + (4.10 m )} + (4.10 m )k to a final position of ä, - (5.80 m )i + (1.80 m )) + (7.20 m )k in 3.60 s. Find (a) the work done on the object by the force in the 3.60 s nda, interval, (b) the...

  • Force F = (-5.3 N) ? + (3.2 N); acts on a particle with position vector...

    Force F = (-5.3 N) ? + (3.2 N); acts on a particle with position vector 7 = (2.4 m) î + (3.9 m)). what are (a) the magnitude of the torque on the particle about the origin and (b) the angle between the directions of 7 and 7 (a) Number Units (b) Number Units

  • 6) At one instant, force F 4.0j N acts on a 0.25 kg object that has...

    6) At one instant, force F 4.0j N acts on a 0.25 kg object that has position vector (2.0-2.0k) m and velocity vector (-50i+5.0k) m/s. About the origin and in unit vector notation, what are (a) the object's angular momentum and (b) the torque acting on the object?

  • At one instant, force F 4.7i N acts on a 0.374 kg object that has position...

    At one instant, force F 4.7i N acts on a 0.374 kg object that has position vector (7.80-7.80f) m and velocity vector V - (-1.11+1.11K) m/s. About the origin and in unit- vector notation, what are (a) the object's angular momentum and (b) the torque acting on the object?

  • A conservative force F(x) acts on a 2.0 kg particle that moves along an x axis....

    A conservative force F(x) acts on a 2.0 kg particle that moves along an x axis. The potential energy U(x) associated with F(x) is graphed in the figure. When the particle is at x-2.0 m, its velocity is -1.4 m/s. (a) What is F(x) at this position, including sign? Between what positions on the (b) left and (c) right does the particle move? (d) what is its particle's speed at x = 7.0 m? x (m) 10 15 (a) Number...

  • Chapter 08, Problem 077 A conservative force F(x) acts on a 1.7 kg particle that moves...

    Chapter 08, Problem 077 A conservative force F(x) acts on a 1.7 kg particle that moves along an x axis. The potential energy u(x) associated with F(x) is graphed in the figure. When the particle is at x = 2.0 m, its velocity is -1.9 m/s. (a) What is F(x) at this position, including sign? Between what positions on the (b) left and (c) right does the particle move? (d) What is its particle's speed at x = 7.0 m?...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT