Homework Answers
Use dot product of displacement and force to find the required
work and divide the work by time to find the power as shown
below
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physics problem
A force F = (9.60 N)i + (6.30 N)j + (7.00 N )* acts...
A force F = (3.10N) î +(7.20N)ị + (7.30 N) k acts on a 6.30 kg...
A force F = (3.10N) î +(7.20N)ị + (7.30 N) k acts on a 6.30 kg mobile object that moves from an initial position à ; = (6.60m) î + (5.40 m)ſ +(3.80 m) Ê to a final position of ds = (6.20m) î +(7.70 m) Î + (3.30 m) î in 8.50 s. Find (a) the work done on the object by the force in the 8.50 s interval, (b) the average power due to the force during that...
A force 7 = (7.40 N ))+ (9.70 N)} + (8.60 N JK acts on a...
A force 7 = (7.40 N ))+ (9.70 N)} + (8.60 N JK acts on a 9.30 kg mobile object that moves from an initial position of 0; = (7.10 m )i + (4.10 m )} + (4.10 m )k to a final position of ä, - (5.80 m )i + (1.80 m )) + (7.20 m )k in 3.60 s. Find (a) the work done on the object by the force in the 3.60 s nda, interval, (b) the...
PRINTER VERSION BACK NEXT Chapter 07, Problem 041 SN incorrect. with x in meters A single...
PRINTER VERSION BACK NEXT Chapter 07, Problem 041 SN incorrect. with x in meters A single force acts on a particle-like object of mass m kg in such a way that the position of the object as a function of time is given by x 3.4 and t in seconds. Find the work done on the object by the force between 0 and time t. Express your answer in terms of the variables given. m(61-8)(31-(41) +) Edit Click if you...
A force Fi f 6.30 unts acts on an object at the origin in 0- 51.0°...
A force Fi f 6.30 unts acts on an object at the origin in 0- 51.0° above the positive x-axis. (See the figure below.) second force F2 of magnitude 5.00 units acts on the object in the direction of the postive y-axis. Find graphicaly the magnitude and direction of the resultant force FiF magnitude direction
04 Torce - (2.001 + 9.00J + J.JUK) N acts on a 2.90 kg object that...
04 Torce - (2.001 + 9.00J + J.JUK) N acts on a 2.90 kg object that moves in time interval 2.10 s from an initial posi- tion 7= (2.70i - 2.90j + 5.50k) m to a final position 72 = (-4.10i + 3.30j + 5.40k) m. Find (a) the work done on the object by the force in that time interval, (b) the average power due to the e Pare = 2 force during that time interval, and (c) the...
A force F = (3xi - 2xyj) N acts on an object as the object moves...
A force F = (3xi - 2xyj) N acts on an object as the object moves in the .x direction origin to .v 5.00 m (no motion in v-axis). The object has a mass m = 5.00 kg. Find the work done on the object by the force F. lf the object starts from rest, what is the final speed of the object at x = 5.00 m.?
Force F = (-5.3 N) ? + (3.2 N); acts on a particle with position vector...
Force F = (-5.3 N) ? + (3.2 N); acts on a particle with position vector 7 = (2.4 m) î + (3.9 m)). what are (a) the magnitude of the torque on the particle about the origin and (b) the angle between the directions of 7 and 7 (a) Number Units (b) Number Units
Problem 3: A force F = 4x2 - 3x acts on an object as it moves...
Problem 3: A force F = 4x2 - 3x acts on an object as it moves along the x-axis. a) How much work is done by the force as the object moves from x = 2.0 m to x = 7.0 m? b) If the mass of the object is 5.0 kg and it started at rest, what is it's speed at x = 7.0 m? Please show step-by-step.
A force F = 61 N i acts on an object at a point (x0, y0)...
A force F = 61 N i acts on an object
at a point (x0, y0) = (6.2 m, 4.7
m) as shown in the figure. What is the magnitude of the
torque generated by this force about the origin?
What is the magnitude of the torque generated by this force
about the point (x, y) = (2.9 m, 1.6 m)?
Suppose the object is free to rotate about the z axis. If the
object has a moment of inertia...
1) Force F =(-8.00 N){+(6.00 N) j acts on a particle with position vector r =...
1) Force F =(-8.00 N){+(6.00 N) j acts on a particle with position vector r = (3.00 m)i +(4.00 m)j. What are (a) the torque on the particle about the origin, in unit-vector notation, and (b) the angle between the directions of r and F?
A force F = (3.10N) î +(7.20N)ị + (7.30 N) k acts on a 6.30 kg mobile object that moves from an initial position à ; = (6.60m) î + (5.40 m)ſ +(3.80 m) Ê to a final position of ds = (6.20m) î +(7.70 m) Î + (3.30 m) î in 8.50 s. Find (a) the work done on the object by the force in the 8.50 s interval, (b) the average power due to the force during that...
A force 7 = (7.40 N ))+ (9.70 N)} + (8.60 N JK acts on a 9.30 kg mobile object that moves from an initial position of 0; = (7.10 m )i + (4.10 m )} + (4.10 m )k to a final position of ä, - (5.80 m )i + (1.80 m )) + (7.20 m )k in 3.60 s. Find (a) the work done on the object by the force in the 3.60 s nda, interval, (b) the...
PRINTER VERSION BACK NEXT Chapter 07, Problem 041 SN incorrect. with x in meters A single force acts on a particle-like object of mass m kg in such a way that the position of the object as a function of time is given by x 3.4 and t in seconds. Find the work done on the object by the force between 0 and time t. Express your answer in terms of the variables given. m(61-8)(31-(41) +) Edit Click if you...
A force Fi f 6.30 unts acts on an object at the origin in 0- 51.0° above the positive x-axis. (See the figure below.) second force F2 of magnitude 5.00 units acts on the object in the direction of the postive y-axis. Find graphicaly the magnitude and direction of the resultant force FiF magnitude direction
04 Torce - (2.001 + 9.00J + J.JUK) N acts on a 2.90 kg object that moves in time interval 2.10 s from an initial posi- tion 7= (2.70i - 2.90j + 5.50k) m to a final position 72 = (-4.10i + 3.30j + 5.40k) m. Find (a) the work done on the object by the force in that time interval, (b) the average power due to the e Pare = 2 force during that time interval, and (c) the...
A force F = (3xi - 2xyj) N acts on an object as the object moves in the .x direction origin to .v 5.00 m (no motion in v-axis). The object has a mass m = 5.00 kg. Find the work done on the object by the force F. lf the object starts from rest, what is the final speed of the object at x = 5.00 m.?
Force F = (-5.3 N) ? + (3.2 N); acts on a particle with position vector 7 = (2.4 m) î + (3.9 m)). what are (a) the magnitude of the torque on the particle about the origin and (b) the angle between the directions of 7 and 7 (a) Number Units (b) Number Units
A force F = 61 N i acts on an object
at a point (x0, y0) = (6.2 m, 4.7
m) as shown in the figure. What is the magnitude of the
torque generated by this force about the origin?
What is the magnitude of the torque generated by this force
about the point (x, y) = (2.9 m, 1.6 m)?
Suppose the object is free to rotate about the z axis. If the
object has a moment of inertia...
1) Force F =(-8.00 N){+(6.00 N) j acts on a particle with position vector r = (3.00 m)i +(4.00 m)j. What are (a) the torque on the particle about the origin, in unit-vector notation, and (b) the angle between the directions of r and F?
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