A force F = 61 N i acts on an object at a point (x0, y0) = (6.2 m, 4.7 m) as shown in the figure. What is the magnitude of the torque generated by this force about the origin?
What is the magnitude of the torque generated by this force
about the point (x, y) = (2.9 m, 1.6 m)?
Suppose the object is free to rotate about the z axis. If the
object has a moment of inertia I = 64.0
kg·m2 for rotation about the z axis,
what is the magnitude of the angular acceleration of the object due
to the application of the force F?
Homework Answers
Force F = 1.99 N i -3.18 N k acts on a pebble with position vector...
Force F = 1.99 N i -3.18 N k acts on a pebble with position vector T = 0.48 m J -2.20 m k relative to the origin What is the resulting torque on the pebble about the origin? Enter i, j, and k component. What is the resulting torque on the pebble about the point (2.12 m, 0, -3.32 m)? Enter i, j, and k component.
A force F = (3xi - 2xyj) N acts on an object as the object moves...
A force F = (3xi - 2xyj) N acts on an object as the object moves in the .x direction origin to .v 5.00 m (no motion in v-axis). The object has a mass m = 5.00 kg. Find the work done on the object by the force F. lf the object starts from rest, what is the final speed of the object at x = 5.00 m.?
A force F of magnitude 6.20 units acts on an object at the origin in a...
A force F of magnitude 6.20 units acts on an object at the origin in a direction 0 29.00 above the positive x-axis. (See the figure below.) A second force F, of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find graphically the magnitude and direction of the resultant force F1F2. units magnitude O counterclockwise from the +x-axis direction
6) At one instant, force F 4.0j N acts on a 0.25 kg object that has...
6) At one instant, force F 4.0j N acts on a 0.25 kg object that has position vector (2.0-2.0k) m and velocity vector (-50i+5.0k) m/s. About the origin and in unit vector notation, what are (a) the object's angular momentum and (b) the torque acting on the object?
At one instant, force F 4.7i N acts on a 0.374 kg object that has position...
At one instant, force F 4.7i N acts on a 0.374 kg object that has position vector (7.80-7.80f) m and velocity vector V - (-1.11+1.11K) m/s. About the origin and in unit- vector notation, what are (a) the object's angular momentum and (b) the torque acting on the object?
A force Fi f 6.30 unts acts on an object at the origin in 0- 51.0°...
A force Fi f 6.30 unts acts on an object at the origin in 0- 51.0° above the positive x-axis. (See the figure below.) second force F2 of magnitude 5.00 units acts on the object in the direction of the postive y-axis. Find graphicaly the magnitude and direction of the resultant force FiF magnitude direction
Force = 2.11 N i -3.19 N k acts on a pebble with position vector =...
Force = 2.11 N i -3.19 N k acts on a pebble with position vector = 0.51 m j -2.12 m k relative to the origin. What is the resulting torque on the pebble about the origin? Enter i, j, and k component. What is the resulting torque on the pebble about the point (2.02 m, 0, -3.25 m)? Enter i, j, and k component.
Force F = (-5.3 N) ? + (3.2 N); acts on a particle with position vector...
Force F = (-5.3 N) ? + (3.2 N); acts on a particle with position vector 7 = (2.4 m) î + (3.9 m)). what are (a) the magnitude of the torque on the particle about the origin and (b) the angle between the directions of 7 and 7 (a) Number Units (b) Number Units
A force F, with components Fx = 3 N, Fy = 9N, and Fx = 3 N acts on a particle located at r
A force F, with components Fx = 3 N, Fy = 9N, and Fx = 3 N acts on a particle located at r, with components rx = 6 m. ry = 3 m, and rz = 3 m. What is the magnitude of the torque about the origin due to this force? Do not include units. Round your answer to the nearest whole number. Torque Magnitude = __Nm
A force F1 of magnitude 6.70 units acts on an object at the origin in a direction
A force \(\vec{F}_{1}\) of magnitude 6.70 units acts on an object at the origin in a direction \(\theta=48.0^{\circ}\) above the positive x-axis. (See the figure below.) A second force \(\vec{F}_{2}\) of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find graphically the magnitude and direction of the resultant force \(\vec{F}_{1}+\vec{F}_{2}\)
Force F = 1.99 N i -3.18 N k acts on a pebble with position vector T = 0.48 m J -2.20 m k relative to the origin What is the resulting torque on the pebble about the origin? Enter i, j, and k component. What is the resulting torque on the pebble about the point (2.12 m, 0, -3.32 m)? Enter i, j, and k component.
A force F = (3xi - 2xyj) N acts on an object as the object moves in the .x direction origin to .v 5.00 m (no motion in v-axis). The object has a mass m = 5.00 kg. Find the work done on the object by the force F. lf the object starts from rest, what is the final speed of the object at x = 5.00 m.?
A force F of magnitude 6.20 units acts on an object at the origin in a direction 0 29.00 above the positive x-axis. (See the figure below.) A second force F, of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find graphically the magnitude and direction of the resultant force F1F2. units magnitude O counterclockwise from the +x-axis direction
6) At one instant, force F 4.0j N acts on a 0.25 kg object that has position vector (2.0-2.0k) m and velocity vector (-50i+5.0k) m/s. About the origin and in unit vector notation, what are (a) the object's angular momentum and (b) the torque acting on the object?
At one instant, force F 4.7i N acts on a 0.374 kg object that has position vector (7.80-7.80f) m and velocity vector V - (-1.11+1.11K) m/s. About the origin and in unit- vector notation, what are (a) the object's angular momentum and (b) the torque acting on the object?
A force Fi f 6.30 unts acts on an object at the origin in 0- 51.0° above the positive x-axis. (See the figure below.) second force F2 of magnitude 5.00 units acts on the object in the direction of the postive y-axis. Find graphicaly the magnitude and direction of the resultant force FiF magnitude direction
Force F = (-5.3 N) ? + (3.2 N); acts on a particle with position vector 7 = (2.4 m) î + (3.9 m)). what are (a) the magnitude of the torque on the particle about the origin and (b) the angle between the directions of 7 and 7 (a) Number Units (b) Number Units
A force \(\vec{F}_{1}\) of magnitude 6.70 units acts on an object at the origin in a direction \(\theta=48.0^{\circ}\) above the positive x-axis. (See the figure below.) A second force \(\vec{F}_{2}\) of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find graphically the magnitude and direction of the resultant force \(\vec{F}_{1}+\vec{F}_{2}\)
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