Question

Force F = 1.99 N i -3.18 N k acts on a pebble with

0 0
Add a comment Improve this question Transcribed image text
Answer #1

て2-1, 53个_ 4.381.0-55、k ん2-2.12个+0.48个+1.12企 2

Add a comment
Know the answer?
Add Answer to:
Force F = 1.99 N i -3.18 N k acts on a pebble with position vector...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Force = 2.11 N i -3.19 N k acts on a pebble with position vector =...

    Force = 2.11 N i -3.19 N k acts on a pebble with position vector = 0.51 m j -2.12 m k relative to the origin. What is the resulting torque on the pebble about the origin? Enter i, j, and k component. What is the resulting torque on the pebble about the point (2.02 m, 0, -3.25 m)? Enter i, j, and k component.

  • Chapter 11, Problem 023 rce 7-(954N)cts enn 7(1.06m)j ForceF(9.54 N)i-6.91 Nk acts on a pebble with...

    Chapter 11, Problem 023 rce 7-(954N)cts enn 7(1.06m)j ForceF(9.54 N)i-6.91 Nk acts on a pebble with position vector(1.06 m)j- 5.46m k, relative to the origin. What is the resulting torque acting on the pebble about (a) the origin and (b) a point with coordinates (7.93 m, 0, -9.12 m)? k Units (a) Number K Units (b) Number

  • FULL SCREEN PRINTEM VERSION NEXE BACK Chapter 11, Problem 023 Force F = (2.78 N)i -...

    FULL SCREEN PRINTEM VERSION NEXE BACK Chapter 11, Problem 023 Force F = (2.78 N)i - (2.29 N ) acts on a pebble with position vector r=(3.61 m)j-(3.95 m k, relative to the origin. What is the resulting torque acting on the pebble about (a) the angin and (b) a point with coordinates (5.31 m, 0, -5.04 m)? (a) Number k Units (b) Number Units T Click if you would like to Show Work for this question: Open Show Work...

  • 1) Force F =(-8.00 N){+(6.00 N) j acts on a particle with position vector r =...

    1) Force F =(-8.00 N){+(6.00 N) j acts on a particle with position vector r = (3.00 m)i +(4.00 m)j. What are (a) the torque on the particle about the origin, in unit-vector notation, and (b) the angle between the directions of r and F?

  • Force F = (-5.3 N) ? + (3.2 N); acts on a particle with position vector...

    Force F = (-5.3 N) ? + (3.2 N); acts on a particle with position vector 7 = (2.4 m) î + (3.9 m)). what are (a) the magnitude of the torque on the particle about the origin and (b) the angle between the directions of 7 and 7 (a) Number Units (b) Number Units

  • At one instant, force F 4.7i N acts on a 0.374 kg object that has position...

    At one instant, force F 4.7i N acts on a 0.374 kg object that has position vector (7.80-7.80f) m and velocity vector V - (-1.11+1.11K) m/s. About the origin and in unit- vector notation, what are (a) the object's angular momentum and (b) the torque acting on the object?

  • A force F = 61 N i acts on an object at a point (x0, y0)...

    A force F = 61 N i acts on an object at a point (x0, y0) = (6.2 m, 4.7 m) as shown in the figure. What is the magnitude of the torque generated by this force about the origin? What is the magnitude of the torque generated by this force about the point (x, y) = (2.9 m, 1.6 m)? Suppose the object is free to rotate about the z axis. If the object has a moment of inertia...

  • 6) At one instant, force F 4.0j N acts on a 0.25 kg object that has...

    6) At one instant, force F 4.0j N acts on a 0.25 kg object that has position vector (2.0-2.0k) m and velocity vector (-50i+5.0k) m/s. About the origin and in unit vector notation, what are (a) the object's angular momentum and (b) the torque acting on the object?

  • A particle is located at the vector position i = (2 + 4)m and the force...

    A particle is located at the vector position i = (2 + 4)m and the force acting on it is f = 4i +3j N. What is the torque about the origin? O (-10.0 Nm) (-11.0 Nm)k (-10.0 Nm) (7.00 Nm)ſ (10.0 Nm)

  • A particle moves through an xyz coordinate system while a force acts on the particle. When...

    A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector r Overscript right-arrow EndScripts = (2.00 m) i Overscript ̂ EndScripts - (3.00 m) j Overscript ̂ EndScripts + (2.00 m) k Overscript ̂ EndScripts, the force is Upper F Overscript right-arrow EndScripts = Fx i Overscript ̂ EndScripts + (7.00 N) j Overscript ̂ EndScripts - (6.00 N) k Overscript ̂ EndScripts, and the corresponding torque about...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT