A 10.8 kg block is placed at rest on a plane inclined at 29 o. If...
A 10.8 kg block is placed at rest on a plane inclined at 29 o. If after moving 6 meters, the block has a velocity of magnitude 6.3 m/s, what is the coefficient of friction between the block and the plane?
Homework Answers
friction force f = uN
N = mgcos29
so f = umgcos29
using work energy theorem,
work done by gravity + work done by friction = change in KE
mgLsin29 + ( - umgcos29 L ) = mv^2 /2 - 0
(9.81 x 6 x sin29) - ( u x 9.81 x cos29 x 6) = 6.3^2 /2 - 0
28.54 - u51.48 = 19.845
u = 0.17
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