Solution,
Using standard normal table,
a) P( 1 Z 2)
= P( Z 2) - P( Z 1)
= 0.9772 - 0.8413
= 0.1359
b) P( -0.25 < Z < 0.8)
= P( Z < 0.8) - P( Z < -0.25)
= 0.7881 - 0.4013
= 0.3868
c) P( Z = 0)
= 0.5
d) P(Z -1)
= 1 - P( Z -1)
= 1 - 0.1587
= 0.8413
4. Let Z ~ N(0,1) be a standard normal variable. Calculate the probability (a) P(1 <Z...
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