Question

Need numbers 1, 2, 3, 4, 5, and 7 worked out with the correct answers shown. Please show all work and make sure the picture you upload is clear and not blurry. Also no shortcuts please when working out the problems.

Answer 1

Answer 2

An object has kinetic energy of 275 J and a momentum of magnitude 25.0 kg.m/s. Find the speed and mass of the object.

K = p²/2m

275 = (25)²/2m

m = 625/2/275 = 1.14 kg

K =

Answer 3

0.03 kg bullet fired vertically at 200 m/s into a 0.15kg baseball that is initially at restHow high does the combination rise after the collision, assuming the bullet embeds itself in the ball?

0.03 . 200 = 0.18 . V

V = 33.33 m/s

H = V^2 / 2 . g = 57.7 m

Answer 4

A baseball outfielder throws a baseball of mass 0.15 kg at a speed of 40 m/s and initial angle of 30 degree with horizontal. What is the kinetic energy of the baseball at the highest point of the trajectory?

The horizontal component of speed
= 40 m/s * cos(30)
=40 cos(30) m/s
mass
=0.15 kg
Since at the highest point, vertical velocity=0, and horizontal velocity is unchanged (ignore air resistance), so
K.E.=mv^2/2=0.15*(40cos(30))^2/2
=0.15*1600*3/4/2
=90 joules