Question

Unit 15 Workshop: Integrated Chemistry Review 1. A hydrocarbon is analyzed and found to contain 85.7% C and 14.3% H. a. What is the empirical formula for this hydrocarbon? The molar mass is 28.0 g/mol, what is the molec- ular formula for this hydrocarbon? n = 45.7g molor most of ng Imol reparo carton = 28 Oglinda n - 14.39 H Talmol = 7.14 mol е че има b. Draw the Lewis structure, then identify the molecular geometry and the hybridization on each carbon of the hydrocarbon. molecular geometry H-6=¢ -HI sp² sp² H-c- 6-H ť 4 The hydrocarbon reacts with HCl in the gas phase as a single-collision combination reaction using the unhybridized p orbitals to form the product. c. Write the balanced reaction. H H U --> C, M d. Draw the Lewis structure, then identify the molecular geometry and the hybridization on each carbon of the product. hybridization of both - a carbons B Sp3 e. Draw a representation of the collision between the hydrocarbon and the HCl molecule that leads to the product. Explain why you think this is an effective collision.

Answer 1

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moles ho 12 C = 85.7 H = 14:3 7.15 Simplest Ratio 5:15 = 1 14 3 =2 Mc = 8.527 = 7:15 ha= 143 = 143 7.15 . Empirical formula = C H₂ Empirical formula Mass = 12 +2 => 14 ASUS Moleculad Mass = 28 Molecular Mass = n x Emibitical formula mars - 28= nxiu n=2 - Moleculas formula = 2 CC, H2) = Cz Hy D - . Empirical formula CH₂ Molecular " C2 Hu 12 Hybridisation of Both oreometry Health carbon an 12 C2 HU + HCl - C2H5C1 H ECT THU - H-¢- 6-CI H H Bond Effective At A Break Mybridisation of Product V Dodsation of Poduct at Both Casbon are SP3 AB+ AB New Bonds formed . ALAT B-B Collision B-LB A-B Ineffective Collision A--- A - A A +B=6 In this bonds are not formed Blw A-B CSscanned with CamScanner . .

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