Question

3. Determine the limiting reactant and the mass of AlCl3 produced by reacting 15.0 g of Al with 30.0 g of Cly according to the following chemical equation. The molar mass of AICI is 133.33 g/mol. A1 = 26.98 g/mol 2 Al(s) + 3 Cl2 (g) → 2 AlCl3(s) C1 = 35.45 g/mol A) Al is the limiting reactant, 32.4 g of AlCl3 produced. B) Al is the limiting reactant, 74.1 g of AlCl3 produced. C) Cl2 is the limiting reactant, 37.6 g of AlCl3 produced. D) Cl2 is the limiting reactant, 56.3 g of AlCl3 produced. E) Cl2 is the limiting reactant, 75.2 g of AICI: produced.

Answer 1

Lanzo 2 Alls) + 3 cl₂(g) → 2 Ale13 (3) f 2 Mole 3 Mole 2 mole | Al= 26.9. 53.8 g * 21279 266.59 L4 : 35.458 Reaction 15g Al with 30 g of cly Limiting agent is ela (nees = 18638 = 28.8.27 mol -C2 z 30 g = 0.14 ms 212.7 g la creaction producers 266.5g Alelz 30 ģ " ( 266.5*30) g Ally 21207 = 37.88 g Alels, 37.6 g Aids Answer 7 6 Limiting agent - el, 37.6 g Alely prod deed, 2127 Scanned with CamScanner