2Al(s) + 3Cl2(g) → 2AlCl3(s)
Determine the mass (in g) of AlCl3 formed if 74.6 g of Al reacts with 74.6 g of Cl2.
2Al(s) + 3Cl2(g) → 2AlCl3(s) Determine the mass (in g) of AlCl3 formed if 74.6 g...
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)?2AlCl3(s) What is the maximum mass of aluminum chloride that can be formed when reacting 27.0 g of aluminum with 32.0 g of chlorine?
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)?2AlCl3(s) What is the maximum mass of aluminum chloride that can be formed when reacting 17.0g of aluminum with 22.0g of chlorine?
Use standard enthalpies of formation to determine ΔHorxn for:2Al(s) + 3Cl2(g) →2AlCl3(s)Enter in kJ.
Given the reaction: 2Al (s)+ 3Cl2 (g) ---->2AlCl3 (s) 1. Find the limiting reactant if 82.5g of Al and 247g of Cl2 are used? 2. What is the theoretical yield? Someone, please help me understand this, I tried the problem on my own, I just need to make sure I went about it the right way!
1)Use: 2Al + 6HCl → 3H2 + 2AlCl3 a) If 5.34 g H2 are formed, how many grams of Al reacted? b) If 2.500 kg Al reacts, how many moles of H2 are produced? c) If 6.13 moles of Al react, how many moles of HCl need to react? d) If 125.00 moles HCl reacts, how many mg of AlCl3 are produced? e) If 4.81 x 1024 formula units of AlCl3 are produced, how many moles of HCl reacted?
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are given 16.0 g of aluminum and 21.0 g of chlorine gas. If you had excess aluminum, how many moles of aluminum chloride could be produced from 21.0 g of chlorine gas, Cl2? Express your answer to three significant figures and include the appropriate units.
Calculate the total masses of the reactants for the following equation: 2Al(s)+3Cl2(g)→2AlCl3(g)
Aluminum reacts with chlorine gas to form aluminum chloride. 2Al(s)+3Cl2(g)→2AlCl3(s) What minimum volume of chlorine gas (at 298 KK and 217 mmHgmmHg) is required to completely react with 8.48 gg of aluminum?
The reaction of aluminum with chlorine gas is shown.2Al+3Cl2⟶2AlCl3How many units of aluminum chloride (AlCl3) can be produced from 30 aluminum atoms?number of AlCl3 units: _________________
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are given 13.0 g of aluminum and 18.0 g of chlorine gas. Part A If you had excess chlorine, how many moles of of aluminum chloride could be produced from 13.0 g of aluminum? Express your answer to three significant figures and include the appropriate units. If you had excess aluminum, how many moles of aluminum chloride could be produced from 18.0 g of chlorine...