A survey of 100 respondents as conducted to study proportion people snoring in their sleep. Approximately 40% people claim that they do. Using this information , construct a 95% confidence interval for the proportion of people that do snore in their sleep.
We need at least 9 more requests to produce the answer.
1 / 10 have requested this problem solution
The more requests, the faster the answer.
Use the degrees of confidence and a sample data to construct a 95% confidence interval for the population proportion. A survey of 200 union members in New York reveals that 112 favor the republican candidate for governor.
Using the sample of size 200, construct a 95% confidence interval for the proportion of Youth Survey participants who would describe themselves as being about the right weight (Round to three decimal places.) Sample Proportion = Margin of error Lower limit Upper limit Does your 95% confidence interval based on the sample of size 200 include the true proportion of Youth Survey participants who would describe themselves as being about the right weight? O Yes O No
Construct a 95% confidence interval of the population proportion using the given information. x = 75, n = 150 The lower bound is _______ The upper bound is _______
For the situation below, construct the 95% confidence interval estimate to the population. assume that the results are based on a nationally representative sample. Express the estimate in a sentence. Of the 998 respondents questioned, 246 identified themselves as Catholic. Problem 2: The 40-hour work week is generally considered as a standard in American society today. Using data from the 2006 General Social Survey, you wish to determine whether the mean number of hours worked per week by men in...
Answers only is okay! Construct the indicated confidence interval for the population mean μ using the t-distribution. Assume the population is normally distributed. c=0.99, x=13.1, s=3.0, n= 6 Construct the indicated confidence interval for the population mean μ using the t-distribution. Assume the population is normally distributed. c=0.95, x=14.5, s=0.55, n= 15 Use the given confidence interval to find the margin of error and the sample mean. (12.7,19.9The sample mean is In a random sample of 18 people, the mean...
a. Construct a 95% confidence interval estimate of the population proportion of adults who had bought something online b. Construct a 95% confidence interval estimate of the population proportion of online shoppers who are weekly online shoppers. A research center survey of 2,351 adults found that 1,899 had bought something online. Of these online shoppers, 1,203 are weekly online shoppers. Complete parts (a) through (c) below.
Question 19 (5 points) A pollster wants to construct a 95% confidence interval for the proportion of adults who believe that economic conditions are getting better. A Gallup poll taken in July 2010 estimates this proportion to be 0.33. Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.039? Write only an integer as your answer. Your Answer: Answer Question 20 (5 points) A researcher wants to construct a...
Out of 500 people sampled, 450 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids. Do not use StatCrunch. Show all formulas used, work and steps. Be sure to define your variables. As in the reading, in your calculations: --Use z = 1.645 for a 90% confidence interval --Use z = 1.96 for a 95% confidence interval --Use z = 2.576 for a 99% confidence interval Give your answer in...
In a survey of 2280 adults, 709 say they believe in UFOS. Construct a 95% confidence interval for the population proportion of adults who believe in UFOS. A 95% confidence interval for the population proportion is ( (Round to three decimal places as needed.) ) Interpret your results. Choose the correct answer below O A. With 95% confidence, it can be said that the population proportion of adults who believe in UFOS is between the endpoints of the given confidence...
Construct a 95% confidence interval of the population proportion using the given information. x = 120, n = 200 The lower bound is The upper bound is (Round to three decimal places as needed.)