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04: For the RC circuit shown with its natural response during the charging and discharging process in DC. Find the following:

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at Volt) - 12 2(1-p-t/r,c) Now, we have ic (t) = c d Velt) ie(t)= 120 d (1-e-t|R,c) delt) = 1266-e-tlac) ( since & (e-ax)= x-ve(t) = 121 e-(t-ioms)/(R+R2)C) 1=(R+Rac So, when switch is moved to 2 at t = coms; we can write; so ic(t) = cd (120-64-roms)-0.4x10-33 - 12 - (roms-loms)/(R+R2) (R1+R2) il 12 E 0.4x10-3 Ritra R, +R2 12 0.4x10-3 R, + Ra=30kr. on trutting R, = 20kn RaHope it found useful to you. You can comment in case of any queries related to this problem. Thank You...

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