Question

A sample of gaseous PCs was introduced into an evacuated flask so that the pressure of pure PCI would be 0.48 atm at 433 K. H

At a particular temperature, 11.1 mol of SO3 is placed into a 3.8-L rigid container, and the SO3 dissociates by the reaction

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Answer #1

PCl5 = PCl3 + Cl2

Initial 0.48. 0. 0

Change. -X. +X. + X

Equilibrium. (0.48-X). X X

Total pressure = 0.48+X= 0.80

X = 0.32 ATM

0.48-X = 0.48-0.32= 0.16 ATM

Kp = 0.32×0.32/0.16= 0.64 ATM

Ans= Kp= 0.64atm

2. Conct of SO3 = 11.1/3.8= 2.921 M

2SO3. =. 2SO2. +. O2

Initial. 2.92. 0. 0

Change. -2X. +2X. +X

Equilibrium. 2.92-2X. 2X. X

Concentration of so2 at equilibrium = 3/3.8= 0.78947M

SO3 at equilibrium= 2.92-0.78947= 2.1316 M

O2 at equilibrium= 0.78947/2= 0.3947 M

K= 0.39473×0.78947×0.78957/2.1316×2.1316

=0.054

K= 0.054

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