Question

A 100 mol/h liquid oil stream is 20% solute Q. We wish to reduce the concentration...

A 100 mol/h liquid oil stream is 20% solute Q. We wish to reduce the concentration of Q to 1% by stripping it out with air. The air flow rate is 100 moles/h. The Henry’s Law constant for Q is 1.5. Find the outlet gas composition and the number of equilibrium stages.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Y2 x = 1 1 11e - 2000 L=100(1-02) = 80 mol/h Y = 1.5% Gs=100 mayno 40 Ls (x2-x)= G CY2-Y) 80(+ - 99) 100(Y2-0) Ya = 0.1919 mo

Add a comment
Know the answer?
Add Answer to:
A 100 mol/h liquid oil stream is 20% solute Q. We wish to reduce the concentration...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • You wish to remove solute Q from a heavy oil stream by stripping the oil with...

    You wish to remove solute Q from a heavy oil stream by stripping the oil with air. The stripper is expected to operate at 60°C and 2.2 atm pressure. At this temperature and pressure the oil can be considered to be nonvolatile and the air is insoluble in the oil. The inlet liquid flows at 100 kgmole/hr (total flow) and is 20 mole% Q. You wish to reduce the concentration of Q in the oil to 1 mole% Q. The...

  • (b) Propane must be stripped from an oil stream in a stripping column by using pure...

    (b) Propane must be stripped from an oil stream in a stripping column by using pure steam The pure oil stream (without Propane) has a flow-rate of 150kmol/h and is loaded with 2.5 mol% Propane. The column is set at the temperature of 350 K and pressure of 1.2 atm. The minimum propane amount to be separated is 90% (1) In order to determine the flow of the gas stream, some assumptions are used. What are the assumptions 3 Marks...

  • 2. A gas mixture at 1.0 atm pressure containing air and solute A is contacted in...

    2. A gas mixture at 1.0 atm pressure containing air and solute A is contacted in a single stage mixer continuously with pure water at 30 °C. The two exit gas and liquid streams reach equilibrium. The inlet gas flow rate is 100 kg mol/h, with a mole fraction of A being 0.20. It is desired that the exiting gas contain an A mole fraction of 0.01. Calculate the flow rate of liquid required to achieve this separation. Assume that...

  • (c) A plate- tower is used to recover benzene from air. Gas feed flow rate to...

    (c) A plate- tower is used to recover benzene from air. Gas feed flow rate to the absorber tower is 100kmol/h. The feed gas contains 10 mole percent benzene. The liquid heavy oil to the top tray of the absorber contains no benzene. Its flow rate is 80 kg mol/h. The equilibrium relationship is ye 0.5 xe Assuming constant flow estimate the number of stages for an exit gas composition of 0.5 mole percent benzene at the top of the...

  • Can someone help with this separations problem? sol- A complete gas treatment plant often consists of...

    Can someone help with this separations problem? sol- A complete gas treatment plant often consists of both an absorber to remove ute from air and a stripper to regenerate solvent. Some treated air is heated and is used as stripping gas. In a particular application we wish to remove obnoxious impurity from inlet air. Absorber operates at 1.5 atm and 24.0°C where obnoxious impurity equilibrium is given as y ates at 1.0 atm and 92.0 C where equilibrium is y...

  • Example 12-3. Graphical analysis for more concentrated absorber A gas strearn is 90 mol% N2 and...

    Example 12-3. Graphical analysis for more concentrated absorber A gas strearn is 90 mol% N2 and 10 mol% CO2. We wish to absorb the CO2 into water. The inlet water is pure and is at 5°C. Because of cooling coils, operation can be assumed to be isothermal Operation is at 10 atm If the liquid flow rate is 1.5 times the minimum liquid flow rate, how many equilibrium stages are required to absorb 92% of the CO2? Choose a basis...

  • Problem 5.16 5.16. A stream of air (21 mole% 02, the rest N2) flowing at a rate of 100 kg/h is mixed with a stream...

    Problem 5.16 5.16. A stream of air (21 mole% 02, the rest N2) flowing at a rate of 100 kg/h is mixed with a stream of CO. The CO; enters the mixer at a rate of 20.0 m/h at 150°C and 1.5 bar. What is the mole percent of CO, in the product stream? 5. Problem 5.17 S.17. Spray drying is a process in which a liquid containing dissolved or suspended solids is injected into a chamber through a spray...

  • To absorb CH4 contained in nitrogen by using liquid ammonia. The inlet gas speed is 100...

    To absorb CH4 contained in nitrogen by using liquid ammonia. The inlet gas speed is 100 kmol/h, and the mole fraction of CH4 is 0.2%. It is intended to eliminate 98% of CH4 entering by using pure liquid ammonia as an absorbent. The absorption process operates at 253.2 K, 175 atm, where the equilibrium information of methane is yCH4 = 20 × xCH4. The total flow rate of gases and liquids is assumed to be constant within the absorption tower,...

  • Sorry this is a HUGE problem and I don't even know where to start with this one. Any help is grea...

    Sorry this is a HUGE problem and I don't even know where to start with this one. Any help is greatly appreciated! I rate any correct answers thank you! A 50/50 mixture of 1-propanol and 2-propanol is separated by a continuous single-stage equilibrium flash tank. The liquid entering the tank is at 89.0°C The tank operates at 70.00°C and 330.0 mmHg and both product streams emerge at these conditions Vapor product ny mol yy mol 1-propanol/mol 70.00°C, 330.0 mmv mol...

  • 74 Percent Concentration -The amount of solute dissolved in a fixed amount of solvent is called the concentration of th...

    74 Percent Concentration -The amount of solute dissolved in a fixed amount of solvent is called the concentration of the solution. Concentrations are typically expressed as Mass al.) (% m/m) which is the mass of the solute (g) divided by the mass of the solution [solute+ solvent] (g)x 1000/0; or as Volume ol.) (% v/v ) which is the volume of the solute in a fixed volume of solution (1O0mL of solution) x 1000/0; or less commonly in the laboratory,...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT