Sorry this is a HUGE problem and I don't even know where to start with this one. Any help is greatly appreciated! I rate any correct answers
thank you!
Antoine Equation is given below
where p = vapour pressure (in bar), T=temperature (in K) and A,B,C are Antoine's constant.
Check the values of A,B,C and T from your source, put the values and obtain the vapour pressure for 1-propanol (p1*) and 2-propanol (p2*)
From my source I get p1* = 244.85 mm Hg and p2* = 443.95 mm Hg
1) There are 7 unknowns namely,
nv, nL, y1, y2, x1, x2 and Q
2) Except for the last two we can apply all the independent equations. These are
a) nv y1 + nL x1 = 0.5
b) nv + nL = 1
c) y1 + y2 =1
d) x1 + x2 = 1
e) x1 p1* = 330 y1
f) x2 p2* = 330 y2
g) Energy balance
Q = Hout - Hin
Hin = 20.4898
From Liquid: Hout = 19.2 x1 + 12.6406 x2
From vapour Hout = 59.52 y1 + 40.161 y2
Therefore, 19.2 x1 + 12.6406 x2 + 59.52 y1 + 40.161 y2 - 20.4896 = Q
3) Solving c, d, e and f we get,
x1 = 0.72 and x2 = 0.28, y1=0.60 and y2 = 0.40
4) Putting these in a and using b we bet
Sorry this is a HUGE problem and I don't even know where to start with this one. Any help is grea...
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