A tuning fork vibrates at a frequency of 530 Hz. An out-of-tune piano string vibrates at...

Question

Question

A tuning fork vibrates at a frequency of 530 Hz. An out-of-tune piano string vibrates at 535 Hz. How much time separates successive beats?

Answer 1

Answer #1

Beat frequency = f1 - f2 = 5 Hz

Time seperation = 1/delF = 1/5 = 0.2 seconds

Answer 2

Answer #2

f = 1/t

beat fri = 535-530 = 5Hz

so time = 1/5= 0.2sec

Answer 3

Answer #3

Beats=frequency2-frequency2=535-530

Beats=5

Answer 4

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