Given the equation 4KO2+ 2CO2---> 3K2CO3+ 3O2 ; how much O2 could be produced from 2.50g KO2 and 4.50g CO2
Given the equation 4KO2+ 2CO2---> 3K2CO3+ 3O2 ; how much O2 could be produced from 2.50g...
The reaction between potassium superoxide, KO2, and CO2, 4KO2+2CO2→2K2CO3+3O2 is used as a source of O2 and absorber of CO2 in self-contained breathing equipment used by rescue workers. a). How many moles of O2 are produced when 0.475 mol of KO2 reacts in this fashion? b). How many grams of KO2 are needed to form 8.0 g of O2? c). How many grams of CO2 are used when 8.0 g of O2 are produced?
Potassium superoxide, KO2, reacts with carbon dioxide to form potassium carbonate and oxygen: 4KO2 + 2CO2 2K2CO3 + 3O2 This reaction makes potassium superoxide useful in a self-contained breathing apparatus. How much O2 (in grams) could be produced from 2.45 g of KO2 and 4.62 g of CO2?
Potassium superoxide KO2 reacts with carbon dioxide to form potassium carbonate and oxygen 4KO2(s)+2CO2(g)-->2K2CO3(s)+3O2(g) How many moles of O2 will be produced from 2.50 moles KO2 and 1.50 moles of CO2? Please show work using differential analysis
Methanol (CH3OH) burns according to the equation 2CH3OH(l) + 3O2(g) → 2CO2(g) + 4H2O(l), ΔH°rxn = –1454 kJ/mol. A) How much heat, in kilojoules, is given off when 150.0 g of methanol is burned? [ Select ] B) How many grams of CO2 are produced when the amount of heat determined in part A is released? [ Select ] Molar masses: CH3OH = 32.04 g/mol O2 = 32.00 g/mol CO2 = 44.01 g/mol H2O = 18.02 g/mol
answer according to text book is 29 g of O2 produced from 85g , please show all steps in how to solve! 7.37. Oxygen for First Responders In self-contained breathing devices used by first responders, potassium superoxide, KO2, reacts with exhaled carbon dioxide to produce potassium carbonate and oxygen: 4 KO2(s) +2 CO2(g) 2 K9CO3(s) + 3 O2(g) How much O2 could be produced from 85 g KO2?
Consider the following balanced equation: 3O2(g) + 2CH3OH(l) → 2CO2(g) + 4H2O(l) If 30.3 moles of O2(g) and 31.1 moles of CH3OH(l) are allowed to react to produce 15.0 moles of CO2(g), what is the percent yield of the reaction? a-57.5% b-74.3% c-48.1% d-85.0% e-70.2%
Consider the following balanced chemical equation: C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(l) a. How many moles of CO2 form when 1.53 moles of C2H5OH react? moles CO2 b. How many moles of H2O form from the reaction of 1.53 moles of C2H5OH? moles H2O c. How many moles of CO2 form when 1.53 moles of H2O form? moles CO2 d. How many molecules of CO2 form when 1.53 moles of H2O form? × 10(Click to select)21222324 molecules CO2
For the balanced equation shown below, how many moles of O2 be produced by 0.7236 moles of ZnS? 2ZnS(s) + 3O2 (g) --> 2ZnO(s) + 2SO2 (g)
In the reaction below how many moles of water would be produced if you used 3 moles of oxygen gas (O2) and much CH3OH as needed to react with all the oxygen 2CH3OH + 3O2 2CO2 + 4H2O
A reaction vessel contains 8.90 g of CO and 8.90 g of O2. How many grams of CO2 could be produced according to the following reaction? 2CO+O2 --> 2CO2