Potassium superoxide, KO2, reacts with carbon dioxide
to form potassium carbonate and oxygen:
4KO2 + 2CO2 2K2CO3 +
3O2
This reaction makes potassium superoxide useful in a self-contained breathing apparatus. How much O2 (in grams) could be produced from 2.45 g of KO2 and 4.62 g of CO2?
Potassium superoxide, KO2, reacts with carbon dioxide to form potassium carbonate and oxygen: 4KO2 + 2CO2...
Potassium superoxide KO2 reacts with carbon dioxide to form potassium carbonate and oxygen 4KO2(s)+2CO2(g)-->2K2CO3(s)+3O2(g) How many moles of O2 will be produced from 2.50 moles KO2 and 1.50 moles of CO2? Please show work using differential analysis
The reaction between potassium superoxide, KO2, and CO2, 4KO2+2CO2→2K2CO3+3O2 is used as a source of O2 and absorber of CO2 in self-contained breathing equipment used by rescue workers. a). How many moles of O2 are produced when 0.475 mol of KO2 reacts in this fashion? b). How many grams of KO2 are needed to form 8.0 g of O2? c). How many grams of CO2 are used when 8.0 g of O2 are produced?
A self-contained breathing apparatus uses canisters of potassium superoxide, KO2, which consumes the CO2 exhaled by a person and replaces it with oxygen according to the following reaction: 4KO2(s) + 2CO2(g) → 2K2CO3(s) + 3O2(g) (a) What mass of KO2 in g is required to convert 6.30 L of CO2 at 21.0 oC and 656 mmHg into O2? Answer _____________________ (b) What is the rms speed of an O2 molecule at -9.4 oC?
Oxygen masks for producing O2 in emergency situations contain potassium superoxide, KO2. It reacts with carbon dioxide and water in exhaled air to produce oxygen. 4KO2 + 2H2O + 4CO2 → 4KHCO3 + 302 If a person wearing such a mask exhales 0.702 grams of carbon dioxide per minute, how many grams of oxygen are produced in 5 minutes? Assume you have plenty of every other reagent. O 0.510 grams O 0.383 grams 1.91 grams 2.55 grams
potassium superoxide. KO2 reacts with carbon dioxide, CO2 according to the following equations: 4 KO2 + 2 CO2 --> 2 K2CO3 + 3 O2 When 8 moles of KO2 and 3 moles of CO2 react, the limiting reagent and moles of O2 produced is: KO2 limiting, 6.0 moles O2 CO2 limiting, 12.0 moles O2 KO2 limiting, 3.0 moles O2 CO2 limiting, 4.5 moles O2
please provide all the steps 7.37. Oxygen for First Responders In self-contained breathing devices used by first responders, potassium superoxide, KO2, reacts with exhaled carbon dioxide to produce potassium carbonate and oxygen: 4 KO,(s) + 2 CO2(g) – 2 K2CO3(s) + 3 O2(g) How much O, could be produced from 85 g KO,?
7.37. Oxygen for First Responders In self-contained breathing devices used by first responders, potassium superoxide, KO9, reacts with exhaled carbon dioxide to produce potassium carbonate and oxygen: 4 KO2s) 2 CO2g)2 K9CO3(s)+3 O2(g) How much O9 could be produced from 85g KOg?
Potassium superoxide (KO2) reacts with carbon dioxide to produce oxygen in reaction is very fast and nearly quantitative. It is used in submarines, space vehicles, space suits, and by firefighters and miners. 4 KO2(s) + 2 CO2(g) - 2 K2CO3(s) + 3 O2(g) Calculate the mass of KO2 reacted if 355.8 mL of gas is collected over water at 65.0 °C and a barometric pressure of 744.8 torr. (12 pts.) 7. When 12.424 g of (NH4),PO. (FW 149.087 g/mole) is...
answer according to text book is 29 g of O2 produced from 85g , please show all steps in how to solve! 7.37. Oxygen for First Responders In self-contained breathing devices used by first responders, potassium superoxide, KO2, reacts with exhaled carbon dioxide to produce potassium carbonate and oxygen: 4 KO2(s) +2 CO2(g) 2 K9CO3(s) + 3 O2(g) How much O2 could be produced from 85 g KO2?
Given the equation 4KO2+ 2CO2---> 3K2CO3+ 3O2 ; how much O2 could be produced from 2.50g KO2 and 4.50g CO2