Question

2. The electrochemical cell is comprised of a Mo electrode in a 3.87 × 10-1 M solution of Mo3+ (aq) coupled to a Pt electrode in a solution containing H+ (aq) where the pH of the solution is 0.16 and the partial pressure of H2(g) is 1.018 atm. The temperature of the cell is held constant at 25°C.

(a)What is Ecell (in V) for the electrochemical cell? Report your answer to three decimal places in standard notation (i.e., 0.123 V)

(b) If the pH of the the cell compartment on the right is increased to 1.46 while the other partial pressures and concentrations remain the same as in question 2, what will be the new Ecell (in V)? Report your answer to three decimal places in standard notation (i.e., 0.123 V).

Answer 1

Sep-I • Electochemical cele", - which canest Chemical energy to electrical energy. (PD) Stall Now given Now geven mo electrode coupled with Fredrogen elebide to complete the electrochemical cell - stendard reduction potentials for Half cell in Eirost/mo = -0,200 E H+/H2 = o.ov acts as Electrode which has higher Ered value well a cathode and lower Ered well acts a a Anode in elecbochemical cell hene Herez mo electrode Anodes - . Pt (H2) electrode cathode Reaction at Anode conidation): Moss Moshat se Reaebmat cathode ( Reduet my 3H+ + 38 . 3 H2 (8) Net celle Reaction : Scanned MACS) + 3H ter → More +1246) ar CamScanner

Naast equation at Zsoc Ecem Eirou -0.0591 og forth (w t] (9) [H+] 3 Ecem Ered (Cathodes - Ered (Anads = 0.0-(-0.20) = +0.20v pH of solution = D.16 pr= -log[ht] [ht]= 10PH univen 3 10-0.16 [HH]=0.691m [ Mo3+3 = 3.87X10-1 m PH2 = 1.018 atm m =3 i 0.387) Hone 0.30-0.65qling (s.org ,0367 Eccemu to.20-005 towu- = +0.90 -0.0591 x 0.080 Eccel 0.198 V) (b) If pH imeressed to 1.46 [H+3= 10pH = 101.46 = 0.0346m Ecent 0.20 - Doosani og 1.col.4.0 = 0.20 -0.0591x 3.983 0.121 v Eren - Scaleed with CamScanner