Question

1. Quantitatively compare the coefficients to what you expect from your frequency equation (i.e. by the harmonic number, linear mass density of the cord and its length)

2. Length of the cord is 0.39m, Calculated mass/length (kg/m) is 0.004, mass of the cord is 0.0016kg, harmonic was 3 through the entire experiment

Signal Generator [Table tite here ] ▼ 850 Output 1 Set ◆ Set Run #10 Run # 10 Waveform S weep Type Off Frequency Phase Shift Amplitude Output Frequency (Hz) Sine Hanging MassTension (kg) 0.050 0.100 0.150 0.200 0.250 38.3 0.49 0.98 1.47 1.96 2.45 18.400 25.299 30.200 35.100 38.300 Line ar Offset and Limits 2 m 23.2 0.43 b2.23 + 0.52 Voltage Offset Voltage Limit Current Limit 1.50 A 15 r= 0.999 On Off Auto This device can be configured on a page by page basis 10 850 Output 2 12 13 14 15 16 17 18 19 20 21 850 Output 3 0 0.0 0.2 0.4 0.6 1.0 1.2 1.4 1.6 23 SQRT Tension (sqrt(N)) 24 [Graph title here]

Answer 1

frequency of nth harmonic is given by , where L is the length of string , T - tension, mu - mass per unit length,so according to that with n=3 ,we should get output frequency = 60.81* ${\sqrt{T}}$ . also fundamental frequency = 20.27* ${\sqrt{T}}$ .

frequency of nth harmonic is given by = squareroot T/mu/2L * n, where L is the length of string, T - tension, mu - mass per unit length, so according to that with n = 3, we should get output frequency = 60.81* squareroot T. also fundamental frequency = 20.27* squareroot T.