Question

Floats.java Use the following calculations for di and d2 in your code: double di = 0; // add .1 to 0 eleven times d1 += 1; // 1 d1 += .1; // 2 d1 += 1; // 3 d1 += 1; // 4 d1 += 1; // 5 d1 += .1; 1/6 d1 += 1; /17 d1 += .1; 118 d1 += 1; // 9 d1 += 1; // 10 d1 += 1; // 11 double d2 = 1 * 11: Write a program to compare di to d2 and print whether that are equal or not. Note that they should indeed be equal (adding 11 times is the same as multiplying by 11)! Sample Output 1.0999999999999999 is equal to 1.1

Answer 1

class Floats
{
   public static void main(String args[])
   {
       double d1 = 0;
       //add 0.1 for 11 times to d1
       d1 += 0.1;
       d1 += 0.1;
       d1 += 0.1;
       d1 += 0.1;
       d1 += 0.1;
       d1 += 0.1;
       d1 += 0.1;
       d1 += 0.1;
       d1 += 0.1;
       d1 += 0.1;
       d1 += 0.1;
       //multiply 0.1 with 11
       double d2 = 0.1 * 11;
       //round d1 to 1 decimal place
       double rounded = Math.round(d1 * 10)/10.0;
       //compare the rounded value with d2
       if(rounded == d2)
       {
           //if they are equal print it
           System.out.println(d1 + " is equal to " + d2);
       }
       else
       {
           //if they are not equal print it
           System.out.println(d1 + " is not equal to " + d2);
       }
   }
}

Activities Terminal Sun 10:41 deepika@deepika-TravelMate-P243-M: -/Desktop File Edit View Search Terminal Help deepika@deepika-TravelMate-P243-M:-/Desktops javac Floats.java deepika@deepika-TravelMate-P243-M:-/Desktop$ java Floats 1.0999999999999999 is equal to 1.1, deepika@deepika - TravelMate-P243-M:-/Desktops |

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