Question

Problem 3. One disc performs a translation motion along its horizontal 2

diameter, on a horizontal fixed bar, with the law of motion OA = at . On the periphery of the disc a particle moves with the law of motion BP = s(t) = Rπt2/12. Knowing that a = 10 cm/s2 and R = 25 cm, determine the absolute velocity and acceleration of the particle P at the instant t1 = 2s from the start of the motion.

Problem 3. One disc performs a translation motion along its horizontal diameter, on a horizontal fixed bar, with the law of motion OA = ar'. On the periphery of the disc a particle moves with the law of motion BP = s(t) = Ratt/12. Knowing that a = 10 cm/s and R = 25 cm, determine the absolute velocity and acceleration of the particle P at the instant t= 2s from the start of the motion. 2R Fig. 6.

Answer 1

Twin Data at taas bo to set f Of=ad2 s(d) = R1 a=10m/s R=25cm. Z . ༧. ཚེ wek། = 1༩༧/ ཀ%A + Qe |e ev། ན༡༢༠) Tumy latin. Otzat? Welocity a des saber - Cent) = 2 x lowd = 40 long way acklashian of the (aat)= da = 8x105 go comoldean Ho determal moting, SCH)- PIT RO 10th O= 1742) Trx y z was no 7 (923 - Tech - TIS - T- KOOD ) (1% VaRW. = Pxy = The Are lonton (@= Rota TIR

13ut 20 Total velouity VR = V(Wq-uosino) co Cor = 4o curls NO= 26.179 cmls. OT-60 TVp = 21.716cm)s. Nolio Total Accekmation (90690 1 (rül02 (o sino a Core Sino). Op veg võ (io Lapinoj?+ Corowiskhe)?. > aq=2014/sh 70o = = 13.08 Cm/s - 3 Color >w= 2ax (73% 27.4155. O=>t75. 9R-V 20 - 27.4C360 — 13 8Sin 60 ) + (1300 (260 -- 27.41551160) 925 V 31.9980 + 3945911 -18. 108 cm/