Question

QUESTION 6 What happens to the electric field in the capacitor as the charge, Q, stored in it increases? The field increases as Q. The field decreases as 1/Q. The field increases as Q2. The field decreases as 17Q2.

Answer 1

6)

Option A is the right answer.

The field increases as Q.

Electric field inside the parallel plate capacitor is given by the equation,

$E=\frac{\sigma }{\epsilon _{o}}$

$\sigma =\frac{Q}{A}$

E AER

Εαο

7)

Option B is the right answer.

A parallel plate capacitor creates uniform electric field between two oppositely charged plates