Homework Answers
19) D) 4.0 mm
given
A = 5.0 m^2
dQ/dt = 5000 Watts
k = 0.80 W/(m K)
delta_T = 5.0 C
thickness, L = ?
we know, dQ/dt = k*A*delta_T/L
==> L = k*A*delta_T/(dQ/dt)
= 0.80*5*5/5000
= 0.004 m
= 4.0 mm
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