Question

Please solve using Matlab ONLY

Computational Modeling

The range of an object shot at an angle theta with respect to the x-axis and an initial velocity v0 is given by the trajectory shown below. The Range can be obtained by the following equation,

2 v0 Range =-sin (20) Range

The above equation neglects air resistance and uses standard gravity of g = 9.81 m/s2. Write a matlab code in order to calculate the Range for velocity range 0≤ vo ≤100 m/s and shooting angle range 0 ≤ theta ≤ 90°. Find the angle that gives the maximum range

Answer 1

clc;
maxr = 0.0;
g = 9.81;

for velocity = 1:100
    for angle = 0:90
        range = ((velocity*velocity)/g)*sind(2*angle);
        if (range > maxr)
            maxr = range;
            maxv = velocity;
            maxa = angle;
        end
    end
end

fprintf ('The maximum range is found for velocity = %f m/s and angle = %f degrees.\n', maxv, maxa);
fprintf ('Maximum range = %f m\n\n', maxr);

As you can see above, I have provided you the screenshot of the output and everything is working perfectly.

Let me know if you face any issues. Thank you.