Homework Answers
2Na +2H2O gives 2NaOH + H2 (balanced chemical equation)
We have to find number of moles sodium in 48.9 g (as it is the limiting reagent)
number of moles of sodium = mass of sodium/molar mass of sodium = 48.9/23 = 2.126 moles
from the balanced chemical equation it is clear that 2 moles of Na produce one mole of H2
Thus number of moles of H2 can be formed from the 2.126 moles is 1.063 moles
molar mass of H2 = 2 g/mole
mass of H2 = number of moles x molar mass = 1.063*2 = 2.126 g
The formed amount of H2 molecule is 2.126 g = 2.126 x 10-3 kg
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