Question

bMy courses/b>Blackbox HW Assignment 1.PS 1260X c Get Homework Halo With Che X + € 0 webassign.net/web/Student/Assignment Responses/last/dep-21952949 5. —-/6 points ColFunPhys1 17.P.027. My Notes Ask Your Teacher A beam of electrons is shot into a uniform downward electric field of magnitude 1.04 X 10' N/C. The electrons have an initial velocity of 1.02 X 10 m/s, directed horizontally. The field acts over a small region, 5.00 cm in the horizontal direction. (a) Find the magnitude and direction of the electric force exerted on each electron. magnitude direction -Select- (b) How does the gravitational force on an electron compare with the electric force? The gravitational force is much smaller than the electric force. The gravitational force is much bigger than the electric force. (c) How far has each electron moved in the vertical direction by the time it has emerged from the field? (d) What is the electron's vertical component of velocity as it emerges from the field? (Up is the positive y direction.) (e) The electrons move an additional 21.2 cm after leaving the field. Find the total vertical distance that they have been deflected by the field. Activate Windows Go to sing toovadow A o e a w x TAMO 2019 ] 9 SAMSUNG

Answer 1

solution ! (Q) F=qÈ Magnitude = + 1,6X10-19% 1004x403 = + 1.664 X10-16 N 11.6648 10-16 AM 14 direction = upward (b) ① The gravitational force is much smaller than the electic force. © ay = 1.664 X10% = 1.8285714. 1 918 10-31 X1014m15 so y = hay let) = } x 1.8285714x10'4 (5100x1074 ^ 1602X107) 21,97 x1074 m Y = 21,97 x 10-4 Tmi (d) Vy = ay At = 1.8285714X10'X — Qa4.90196X1079 = 8.9636 xins ms vy=18.9636x105 mis (e) direction af velocity when electron leaves the field = tano = y = 8:96368105 OR tano = 0.0878 8 100 2x107 oz (51022 ) Total vertical distance = 210 97810 m + 21:2 sin (5.022) em so Y Total = 0.2197 cm + 1.85581 cm = 2.67557 cm Total = 2.07551 cm