Question

In fast-pitch softball, a pitcher swings her arm from straight overhead in a circle, releasing the 0.185 kg ball at the bottom of the swing. If a pitcher's arm has a length of 1.10 m and mass of 9.96 kg, and the ball goes from initially at rest to a tangential speed of 29.4 m/s before release, what average torque must the pitcher apply to the ball? Model the pitcher's arm as a uniform thin rod swung about one end, and make sure you don't forget the mass of the softball (but you can ignore its shape; i.e., treat it like a point mass). Hint: you will need to make use of the equations of circular motion for constant angular acceleration that we derived back in week 2.

Answer 1

I = 3 ma 3 kg-m eo - 0,- co2 ML2+ mball L² = L2(M +mban) 9.96 +0.185) (101)2 4.24 so- 180° = rad o, wa 26.73 rad/ w2_wg2+ 20 = (26.73)² = 82 + 2axt =) 113.72 rad/ 4.24x113.72 v 482017 Nm aug Ае =) W = 29.4 lol IC 2 - Laut I = I laug ㄴ