Calculate the molar concentration of OH^- in water solutions with the following H_3O^+ molar concentrations. [H_3...

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Answer 1

Answer #1

[H3O⁺]*[OH^-] = 1.0*10^-14

[OH^-] = 1.0*10^-14/[H3O⁺]

A. [H3O⁺] = 0.068M

[OH^-] = 1.0*10^-14/0.068 = 1.47*10^-13M

B.[H3O⁺] = 5.8*10^-4M

[OH^-] = 1.0*10^-14/5.8*10^-4 = 1.72*10^-11M

C.[H3O⁺] = 0.0068M

[OH^-] = 1.0*10^-14/0.0068 = 1.47*10^-12M

D.[H3O⁺] = 6.0*10^-10M

[OH^-] = 1.0*10^-14/6.0*10^-10 = 1.67*10^-5M

E.[H3O⁺] = 6.0*10^-2M

[OH^-] = 1.0*10^-14/6.0*10^-2 = 1.67*10^-13M

Answer 2

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